HDU 1181 变形课
2016-04-21 18:55
330 查看
http://acm.hdu.edu.cn/showproblem.php?pid=1181BFS搜索建树,找到一条边 b~m那么就输出yes 否则输出no#include<iostream>
#include<cstring>
#include<algorithm>
#include<cstdlib>
#include<vector>
#include<cmath>
#include<stdlib.h>
#include<iomanip>
#include<list>
#include<deque>
#include<map>
#include <stdio.h>
#include <queue>
#define maxn 10000+5
#define ull unsigned long long
#define ll long long
#define reP(i,n) for(i=1;i<=n;i++)
#define rep(i,n) for(i=0;i<n;i++)
#define cle(a) memset(a,0,sizeof(a))
#define mod 90001
#define PI 3.141592657
#define INF 1<<30
const ull inf = 1LL << 61;
const double eps=1e-5;
using namespace std;
bool cmp(int a,int b){
return a>b;
}
string s;
int mp[27][27];
int vis[27];
int bfs()
{
cle(vis);
queue<int>q;
q.push(1);
while(!q.empty())
{
int u=q.front();
q.pop();
for(int i=0;i<26;i++)
{
if(!vis[i]&&mp[u][i])
{
if(i==12)return 1;
q.push(i);
vis[i]=1;
}
}
}
return 0;
}
int main()
{
//freopen("in.txt","r",stdin);
//freopen("out.txt","w",stdout);
while(cin>>s)
{
cle(mp);
mp[s[0]-'a'][s[s.size()-1]-'a']=1;
while(cin>>s)
if(s[0]=='0')break;
else mp[s[0]-'a'][s[s.size()-1]-'a']=1;
if(bfs())cout<<"Yes."<<endl;
else cout<<"No."<<endl;
}
return 0;
}
#include<cstring>
#include<algorithm>
#include<cstdlib>
#include<vector>
#include<cmath>
#include<stdlib.h>
#include<iomanip>
#include<list>
#include<deque>
#include<map>
#include <stdio.h>
#include <queue>
#define maxn 10000+5
#define ull unsigned long long
#define ll long long
#define reP(i,n) for(i=1;i<=n;i++)
#define rep(i,n) for(i=0;i<n;i++)
#define cle(a) memset(a,0,sizeof(a))
#define mod 90001
#define PI 3.141592657
#define INF 1<<30
const ull inf = 1LL << 61;
const double eps=1e-5;
using namespace std;
bool cmp(int a,int b){
return a>b;
}
string s;
int mp[27][27];
int vis[27];
int bfs()
{
cle(vis);
queue<int>q;
q.push(1);
while(!q.empty())
{
int u=q.front();
q.pop();
for(int i=0;i<26;i++)
{
if(!vis[i]&&mp[u][i])
{
if(i==12)return 1;
q.push(i);
vis[i]=1;
}
}
}
return 0;
}
int main()
{
//freopen("in.txt","r",stdin);
//freopen("out.txt","w",stdout);
while(cin>>s)
{
cle(mp);
mp[s[0]-'a'][s[s.size()-1]-'a']=1;
while(cin>>s)
if(s[0]=='0')break;
else mp[s[0]-'a'][s[s.size()-1]-'a']=1;
if(bfs())cout<<"Yes."<<endl;
else cout<<"No."<<endl;
}
return 0;
}
相关文章推荐
- 使用grunt实现css压缩
- #267B. Fedor and New Game-----每日两道水(1)
- PCA的数学原理
- HDU1241 Oil Deposits
- 英语演讲
- ACM牡丹江区域赛
- HDU 5059 help him
- HDU4802 GPA
- 快速排序的递归形式与非递归形式(C++版)
- HDU4496 D-City
- HDU4736-Fibonacci Tree
- 安卓游戏 h5游戏 安卓activity+webview+h5=2048程序员版 只有程序员才能玩的懂的2048升级版html离线小游戏 2048安卓程序员版 android2048
- 常见面试之机器学习算法思想简单梳理
- do-while随机求十个数的和
- HDU4493 Tutor
- HDU2771 Stealing Harry Potter\'s Precious(bfs+dfs)
- HDU 2962 Trucking
- HDU 1839 Delay Constrained Maximum Capacity Path
- HDU 5055 Bob and math problem
- 栈的应用--括号匹配的检验(C++)