leetcode——89——Gray Code
2016-04-19 21:51
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The gray code is a binary numeral system where two successive values differ in only one bit.
Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.
For example, given n = 2, return
Note:
For a given n, a gray code sequence is not uniquely defined.
For example,
For now, the judge is able to judge based on one instance of gray code sequence. Sorry about that.
镜射排列
n位元的格雷码可以从n-1位元的格雷码以上下镜射后加上新位元的方式快速的得到。这种方法基于格雷码是反射码的事实,利用递归的如下规则来构造:
1位格雷码有两个码字
(n+1)位格雷码中的前2^n个码字等于n位格雷码的码字,按顺序书写,加前缀0
(n+1)位格雷码中的后2^n个码字等于n位格雷码的码字,按逆序书写,加前缀1
二进制数转格雷码
(假设以二进制为0的值做为格雷码的0)
G:格雷码 B:二进制码
G(N) = (B(n)/2) XOR B(n)
Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.
For example, given n = 2, return
[0,1,3,2]. Its gray code sequence is:
00 - 0 01 - 1 11 - 3 10 - 2
Note:
For a given n, a gray code sequence is not uniquely defined.
For example,
[0,2,3,1]is also a valid gray code sequence according to the above definition.
For now, the judge is able to judge based on one instance of gray code sequence. Sorry about that.
镜射排列
n位元的格雷码可以从n-1位元的格雷码以上下镜射后加上新位元的方式快速的得到。这种方法基于格雷码是反射码的事实,利用递归的如下规则来构造:
1位格雷码有两个码字
(n+1)位格雷码中的前2^n个码字等于n位格雷码的码字,按顺序书写,加前缀0
(n+1)位格雷码中的后2^n个码字等于n位格雷码的码字,按逆序书写,加前缀1
class Solution { public: vector<int> grayCode(int n) { if (n == 0) return vector<int>(1, 0); vector<int> pre_result = grayCode(n - 1); vector<int> cur_result(pre_result); for (int i = pre_result.size() - 1; i >=0; --i) { cur_result.push_back((1<<(n - 1)) + pre_result[i]); } return cur_result; } };
二进制数转格雷码
(假设以二进制为0的值做为格雷码的0)
G:格雷码 B:二进制码
G(N) = (B(n)/2) XOR B(n)
class Solution { public: vector<int> grayCode(int n) { vector<int> v; for(int i = 0; i < 1 << n; ++ i) v.push_back(i ^ i >> 1); return v; } };
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