leetcode 007 Reverse Integer

Total Accepted:
119423 Total Submissions:
378311 Difficulty: Easy

Determine whether an integer is a palindrome. Do this without extra space.

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package com.archer;
/**
*
* @author Archer
*
* 题意：高位换低位 低位换高位
* 题解： java int 32位  -2147483648----2147483648
*     考虑溢出的问题，可能原数不会溢出，但是转职后会溢出 如测试数据中的1534236469
*/
public class Solution {
publicint reverse(intx) {
longans=0;    //flag 0表示负数，1表示整数

while(x !=0){
ans = ans*10+ x%10;
x /=10;

if(ans >=2147483647 || ans <= -2147483647){
return0;
}
}

return(int)ans;
}

}