您的位置:首页 > 其它

LeetCode *** 205. Isomorphic Strings

2016-04-09 23:59 525 查看
题目:

Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get
t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,

Given
"egg"
,
"add"
, return true.

Given
"foo"
,
"bar"
, return false.

Given
"paper"
,
"title"
, return true.

Note:

You may assume both s and t have the same length.

分析:

用数字来代表是否规律一致即可。

代码:

class Solution {
public:
bool isIsomorphic(string s, string t) {

int sAscii[95]={};
int sRes=0,sI=1;
int tAscii[95]={};
int tRes=0,tI=1;

for(int i=0;i<s.length();++i){
if(!sAscii[s[i]-' ']){
sAscii[s[i]-' ']=sI;
sI++;
sRes=sRes*10+sI;
}
else sRes=sRes*10+sAscii[s[i]-' '];

if(!tAscii[t[i]-' ']){
tAscii[t[i]-' ']=tI;
tI++;
tRes=tRes*10+tI;
}
else tRes=tRes*10+tAscii[t[i]-' '];
}

return sRes==tRes;
}
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: