Codeforces 630J Divisibility
2016-04-09 21:39
183 查看
J. Divisibility
time limit per test
0.5 seconds
memory limit per test
64 megabytes
input
standard input
output
standard output
IT City company developing computer games invented a new way to reward its employees. After a new game release users start buying it actively, and the company tracks the number of sales with precision to each transaction. Every time when the next number of
sales is divisible by all numbers from 2 to 10 every
developer of this game gets a small bonus.
A game designer Petya knows that the company is just about to release a new game that was partly developed by him. On the basis of his experience he predicts that n people
will buy the game during the first month. Now Petya wants to determine how many times he will get the bonus. Help him to know it.
Input
The only line of the input contains one integer n (1 ≤ n ≤ 1018)
— the prediction on the number of people who will buy the game.
Output
Output one integer showing how many numbers from 1 to n are
divisible by all numbers from 2 to 10.
Examples
input
output
求从1到n有多少个数可以被从2到10的数整除,最小公倍数
time limit per test
0.5 seconds
memory limit per test
64 megabytes
input
standard input
output
standard output
IT City company developing computer games invented a new way to reward its employees. After a new game release users start buying it actively, and the company tracks the number of sales with precision to each transaction. Every time when the next number of
sales is divisible by all numbers from 2 to 10 every
developer of this game gets a small bonus.
A game designer Petya knows that the company is just about to release a new game that was partly developed by him. On the basis of his experience he predicts that n people
will buy the game during the first month. Now Petya wants to determine how many times he will get the bonus. Help him to know it.
Input
The only line of the input contains one integer n (1 ≤ n ≤ 1018)
— the prediction on the number of people who will buy the game.
Output
Output one integer showing how many numbers from 1 to n are
divisible by all numbers from 2 to 10.
Examples
input
3000
output
1
求从1到n有多少个数可以被从2到10的数整除,最小公倍数
#include <iostream> #include<cstdio> #include<cstring> #include<cmath> #include<queue> #include<stack> #include<vector> #include<algorithm> using namespace std; int main() { long long n,sum; while(~scanf("%I64d",&n)) { printf("%I64d\n",n/2520); } return 0; }
相关文章推荐
- 数论 2016.4.9
- 欧拉路径和欧拉回路
- 32.线程状态、常用方法
- WOJ 1608 Calculation(状态压缩)
- dw的clicked事件,选中行
- FFmpeg简介
- 回不到开挂的过去,只有前行的探索
- Java8 Stream类学习笔记
- Unicode字符集和多字节字符集关系
- Unicode字符集和多字节字符集关系
- 怎样增强MyEclipse的代码自动提示功能
- 详解使用pscp命令Linux文件上传与下载
- 重载Cocos2D生存期的方法
- 重载Cocos2D生存期的方法
- 重载Cocos2D生存期的方法
- 中缀表达式转后缀并计算值
- Redis命令-有序集合-zinterstore
- x86上的那些UNIX——System V篇(Solaris、SCO)
- 斐波那契数的两种实现方式———1.递归实现,2迭代实现
- 使用CXF发布webService