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hdu1087 LIS变形

2016-04-07 09:59 281 查看
/************************************************
*Author        :jibancanyang
*Created Time  :日  4/ 3 21:23:36 2016
*File Name     :hdu1087.cpp
*题目类型: LIS变形
*很简单的题,但是开始没有把转移方程想好就写,导致了浪费时间...
*定义:dp[i]为以i结尾的最好路径的最大值,然后由它前面的数转移过来就好了.
*************************************************/

#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <cmath>
#include <cstdlib>
#include <ctime>
#include <stack>
using namespace std;
typedef pair<int, int> pii;
typedef long long ll;
typedef unsigned long long ull;
vector<int> vi;
#define xx first
#define yy second
#define sa(n) scanf("%d", &(n))
#define rep(i, a, n) for (int i = a; i < n; i++)
#define vep(c) for(decltype((c).begin() ) it = (c).begin(); it != (c).end(); it++)
#define pr(x) cout << #x << ": " << x << " "
#define prln(x) cout << #x << ": " << x << endl
const int mod = int(1e9) + 7, INF = 0x3fffffff, maxn = 1e5 + 12;
int a[maxn / 100];
ll dp[maxn / 100];
int n;

int main(void)
{
#ifdef LOCAL
//freopen("in.txt", "r", stdin);
//freopen("out.txt", "w", stdout);
#endif
//  cin.sync_with_stdio(false);
while (sa(n), n) {
rep (i, 0, n) {
sa(a[i]), dp[i] = 0;
}
dp[0] = a[0];
rep (i, 1, n) {
for (int j = i - 1; j >= 0; j--) {
dp[i] = max(dp[i], a[i] > a[j] ? dp[j] + a[i] : a[i]);
}
}
ll ans = 0;
rep (i, 0, n) {
ans = max(ans, dp[i]);
}
cout << ans << endl;
}
return 0;
}
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