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j简单的servlet

2016-04-05 09:45 302 查看

1、index.jsp

<body>

    <form action="loginServlet1" method="post">

     <div>

     Name <input type="text" name="name"/><br/>

     Password <input type="text" name="pas"/><br/>

     <input type="submit" value="Login"/>

     <input type="hidden" value="login" name="typeId"/>

     </div>

    </form>

</body>

2、web.xml

<servlet>

     <servlet-name>loginServlet</servlet-name>

        <servlet-class>login.loginServlet</servlet-class>





  </servlet>

         <servlet-mapping>

   <servlet-name>loginServlet</servlet-name>

   <url-pattern>/loginServlet1</url-pattern>

  </servlet-mapping>

3、loginServlet

package login;

import java.io.IOException;

import java.io.PrintWriter;

import javax.servlet.ServletException;

import javax.servlet.http.HttpServlet;

import javax.servlet.http.HttpServletRequest;

import javax.servlet.http.HttpServletResponse;

public class loginServlet extends HttpServlet {

public loginServlet() {

super();

}

public void destroy() {

super.destroy(); // Just puts "destroy" string in log

}

public void doGet(HttpServletRequest request, HttpServletResponse response)

   throws ServletException, IOException {

}

public void doPost(HttpServletRequest request, HttpServletResponse response)

   throws ServletException, IOException {

java.io.PrintWriter out = response.getWriter();



//String type=request.getParameter("typeId");

//if (type.trim().equals("login")) {

String name=request.getParameter("name");//获取视图里的name

String pas=request.getParameter("pas");//获取视图里的password

out.print(pas);

}

public void init() throws ServletException {

}

}

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