您的位置:首页 > 其它

[博弈游戏]Euclid's Game(0099)-SWUST_OJ

2016-04-02 21:13 295 查看
Description

Starts with two unequal positive numbers (M,N and M>N) on the board. Two players move in turn. On each move, a player has to write on the board a positive number equal to the difference of two numbers already on the board; this number must be new, i.e.,
different from all the numbers already on the board. The player who cannot move loses the game. Should you choose to move first or second in this game? 

According to the above rules, there are two players play tihs game. Assumptions A write a number on the board at first, then B write it. 

Your task is write a program to judge the winner is A or B.

Two unequal positive numbers M and N , M>N (M<1000000)
A or B

3 1

A

#include<iostream>
using namespace std;
int main()
{
int m, n, c,x,y;
cin >> m >> n;
x = m;
y = n;
while (y)
{
c = x%y;
x=y;
y = c;
}
m /= x;
if (m % 2)
cout << "A" << endl;
else
cout << "B" << endl;
return 0;
}


利用欧几里得算法将求出最大公约数,而又有规律可知结果与m的奇偶性有关系,使m,n互质,再根据规律得出A还是B会赢得这次比赛
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签:  算法 acm