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android对list对象中的string字符串进行排序

2016-03-31 11:32 555 查看
废话不多说,直接上代码,亲测
public class Person {

public int age;
public String beginTime;
public String name;

public Person(int age, String beginTime, String name) {
super();
this.age = age;
this.beginTime = beginTime;
this.name = name;
}

public Person() {
super();
}

}


public class HahaTime2 {

public static void main(String[] args) {
/**
* 原来的日期
*/
List<Person> list = new ArrayList<Person>();
list.add(new Person(1,"2016-04-22 15:30:28", "小芳"));
list.add(new Person(1,"2016-03-02 15:30:28", "小花"));
list.add(new Person(1,"2016-02-12 15:30:28", "小狗"));
list.add(new Person(1,"2016-12-02 15:30:28", "小猫"));
list.add(new Person(1,"2016-02-02 15:30:28", "小米"));
list.add(new Person(1,"2016-02-12 15:30:28", "小明"));

Collections.sort(list, new MapComparator());
for (Person person : list) {
System.out.println(person.name+";"+person.beginTime);
}
}

}
class MapComparator implements Comparator<Person>{

public int compare(Person lhs, Person rhs) {
return lhs.beginTime.compareTo(rhs.beginTime);
}

}
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