POJ 3273 USACO 2007 Mar Monthly Expense 二分答案
2016-03-26 23:49
309 查看
长度为n的序列分成m块是每块数字之和的最大值最小。
二分答案。
如果按给定和的最大值依次分超过了m块,数字就小了。
否则数字就大了。
正确性怎么证都行。。
Total Submissions: 20927 Accepted: 8198
FJ wants to create a budget for a sequential set of exactly M (1 ≤ M ≤ N) fiscal periods called “fajomonths”. Each of these fajomonths contains a set of 1 or more consecutive days. Every day is contained in exactly one fajomonth.
FJ’s goal is to arrange the fajomonths so as to minimize the expenses of the fajomonth with the highest spending and thus determine his monthly spending limit.
Lines 2..N+1: Line i+1 contains the number of dollars Farmer John spends on the ith day
100
400
300
100
500
101
400
二分答案。
如果按给定和的最大值依次分超过了m块,数字就小了。
否则数字就大了。
正确性怎么证都行。。
#include <cstdio> int main() { static int d[100005]; int n, m, i, ma, s, l, r, mid, c; while (scanf("%d%d", &n, &m) != EOF) { ma = s = 0; for (i = 1; i <= n; ++i) { scanf("%d", d + i); s += d[i]; if (d[i] > ma) ma = d[i]; } l = ma, r = s; while (l < r) { s = c = 0; mid = l + r >> 1; for (i = 1; i <= n; ++i) { s += d[i]; if (s > mid) ++c, s = d[i]; } if (++c > m) l = mid + 1; else r = mid - 1; } printf("%d\n", l); } return 0; }
Monthly Expense
Time Limit: 2000MS Memory Limit: 65536KTotal Submissions: 20927 Accepted: 8198
Description
Farmer John is an astounding accounting wizard and has realized he might run out of money to run the farm. He has already calculated and recorded the exact amount of money (1 ≤ moneyi ≤ 10,000) that he will need to spend each day over the next N (1 ≤ N ≤ 100,000) days.FJ wants to create a budget for a sequential set of exactly M (1 ≤ M ≤ N) fiscal periods called “fajomonths”. Each of these fajomonths contains a set of 1 or more consecutive days. Every day is contained in exactly one fajomonth.
FJ’s goal is to arrange the fajomonths so as to minimize the expenses of the fajomonth with the highest spending and thus determine his monthly spending limit.
Input
Line 1: Two space-separated integers: N and MLines 2..N+1: Line i+1 contains the number of dollars Farmer John spends on the ith day
Output
Line 1: The smallest possible monthly limit Farmer John can afford to live with.Sample Input
7 5100
400
300
100
500
101
400
Sample Output
500Hint
If Farmer John schedules the months so that the first two days are a month, the third and fourth are a month, and the last three are their own months, he spends at most $500 in any month. Any other method of scheduling gives a larger minimum monthly limit.Source
USACO 2007 March Silver相关文章推荐
- 1017 of greedy strategy*
- 常用加密算法的Java实现
- Java学习之字符串类String(一)
- c、c++结构类型
- 文件搜索器
- Python:用generator构造树和遍历(探究yield和yield from)
- 分析一个android程序从建立到启动的过程
- 记一个简单的sql查询
- 1051. 复数乘法 (15)
- 史上最详细的LinkedHashMap详解--源码分析
- 装饰器模式小总结
- Android中Activity转场
- 第四周作业
- MFC 使用位图按钮,并且设置按钮的鼠标悬停效果
- C++中的map
- KSImageNamed-Xcode-master 实用Xcode插件
- cc3000 smartconfig
- 南阳题目168-房间安排
- Android include使用
- 每天一篇python:函数篇