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struts2实现文件下载

2016-03-19 08:56 399 查看
文件下载是一个很常见的功能,用struts2实现文件下载的步骤:

一)定义一个Action类,FileDownload.java

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package com.struts2.filedownload;

import java.io.InputStream;

import org.apache.struts2.ServletActionContext;

import com.opensymphony.xwork2.ActionSupport;

//文件下载

public class FileDownload extends ActionSupport{

private int number ;

private String fileName;

public int getNumber() {

return number;

}

public void setNumber(int number) {

this.number = number;

}

public String getFileName() {

return fileName;

}

public void setFileName(String fileName) {

this.fileName = fileName;

}

//返回一个输入流,作为一个客户端来说是一个输入流,但对于服务器端是一个 输出流

public InputStream getDownloadFile() throws Exception

{

if(1 == number)

{

this.fileName = "Dream.jpg" ;

//获取资源路径

return ServletActionContext.getServletContext().getResourceAsStream("upload/Dream.jpg") ;

}

else if(2 == number)

{

this.fileName = "jd2chm源码生成chm格式文档.rar" ;

//解解乱码

this.fileName = new String(this.fileName.getBytes("GBK"),"ISO-8859-1");

return ServletActionContext.getServletContext().getResourceAsStream("upload/jd2chm源码生成chm格式文档.rar") ;

}

else

return null ;

}

@Override

public String execute() throws Exception {

return SUCCESS;

}

}

二)在struts.xml文件中配置相关信息

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<struts>

<package name="struts2" extends="struts-default">

<action name="FileDownload" class="com.struts2.filedownload.FileDownload">

<result name="success" type="stream">

<param name="contentType">text/plain</param>

<param name="contentDisposition">attachment;fileName="${fileName}"</param>

<param name="inputName">downloadFile</param>

<param name="bufferSize">1024</param>

</result>

</action>

</package>

</struts>

1.结果类型必须要写成 type="stream" ,与之对应的处理类是 org.apache.struts2.dispatcher.StreamResult

2.涉及到的参数:



3.

1) <param name="contentDisposition">attachment;fileName="${fileName}"</param>

contentDisposition默认是 inline(内联的), 比如说下载的文件是文本类型的,就直接在网页上打开,不能直接打开的才会打开下载框自己选择

2) attachment :下载时会打开下载框

3) fileName="${fileName}" :在这定义的名字是一个动态的,该名字是显示在下载框上的文件名字

4.<param name="inputName">downloadFile</param>,这个downloadFile名字要和FileDownload.java类中的getDownloadFile()方法名去掉get 一致

三)用于显示下载的链接界面 filedownload.jsp

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<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>

<%

String path = request.getContextPath();

String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";

%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">

<html>

<head>

<base href="<%=basePath%>">

<title>My JSP 'filedownload.jsp' starting page</title>

<meta http-equiv="pragma" content="no-cache">

<meta http-equiv="cache-control" content="no-cache">

<meta http-equiv="expires" content="0">

<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">

<meta http-equiv="description" content="This is my page">

<!--

<link rel="stylesheet" type="text/css" href="styles.css">

-->

</head>

<body>

<h2>文件下载内容:</h2><br/>

Dream.jpg:<a href="FileDownload.action?number=1">点击下载</a><br/>

jd2chm源码生成chm格式文档.rar:<a href="FileDownload.action?number=2">点击下载2</a>

</body>

</html>
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