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lintcode-medium-Digit Counts

2016-03-18 13:09 363 查看
Count the number of k's between 0 and n. k can be 0 - 9.

if n=12, k=1 in [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12], we have FIVE 1's(1, 10, 11, 12)

class Solution {
/*
* param k : As description.
* param n : As description.
* return: An integer denote the count of digit k in 1..n
*/
public int digitCounts(int k, int n) {
// write your code here

int count = 0;

for(int i = k ; i <= n; i++){
count += singleCount(i, k);
}

return count;
}

public int singleCount(int num, int k){
if(num == 0 && k == 0)
return 1;

int count = 0;

while(num > 0){
if(num % 10 == k)
count++;

num /= 10;
}

return count;
}

};
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