uva11462 Age Sort

水题

#include <cstdio>
#include <queue>
#include <cstring>
#include <iostream>
#include <cstdlib>
#include <algorithm>
#include <vector>
#include <map>
#include <string>
#include <set>
#include <ctime>
#include <cmath>
#include <cctype>
using namespace std;
#define maxn 100000
#define LL long long
int cas=1,T;
int n,x,c[101];
int main()
{
//freopen("in","r",stdin);
//scanf("%d",&T);
while (scanf("%d",&n)!=EOF && n)
{
memset(c,0,sizeof(c));
for (int i = 0;i<n;i++)
{
scanf("%d",&x);
c[x]++;
}
int flag=1;
for (int i = 1;i<=100;i++)
for (int j = 0;j<c[i];j++)
{
if (!flag)
printf(" ");
flag=0;
printf("%d",i);
}
printf("\n");
}
//printf("time=%.3lf",(double)clock()/CLOCKS_PER_SEC);
return 0;
}

You are given the ages (in years) of all people of a country with at least 1 year of age. You know that

no individual in that country lives for 100 or more years. Now, you are given a very simple task of

sorting all the ages in ascending order.

Input

There are multiple test cases in the input file. Each case starts with an integer n (0 < n ≤ 2000000), the

total number of people. In the next line, there are n integers indicating the ages. Input is terminated

with a case where n = 0. This case should not be processed.

Output

For each case, print a line with n space separated integers. These integers are the ages of that country

sorted in ascending order.

Warning: Input Data is pretty big (∼ 25 MB) so use faster IO.

Sample Input

5

3 4 2 1 5

5

2 3 2 3 1

0

Sample Output

1 2 3 4 5

1 2 2 3 3