1108. Finding Average (20)
2016-03-14 23:18
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1108. Finding Average (20)
时间限制400 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者CHEN, YueThe basic task is simple: given N real numbers, you are supposed to calculate their average. But what makes it complicated is that some of the input numbers might not be legal. A "legal" input is a real number in [-1000, 1000] and is accurate up to no morethan 2 decimal places. When you calculate the average, those illegal numbers must not be counted in.Input Specification:Each input file contains one test case. For each case, the first line gives a positive integer N (<=100). Then N numbers are given in the next line, separated by one space.Output Specification:For each illegal input number, print in a line "ERROR: X is not a legal number" where X is the input. Then finally print in a line the result: "The average of K numbers is Y" where K is the number of legal inputs and Y is their average, accurate to 2 decimalplaces. In case the average cannot be calculated, output "Undefined" instead of Y. In case K is only 1, output "The average of 1 number is Y" instead.Sample Input 1:7 5 -3.2 aaa 9999 2.3.4 7.123 2.35Sample Output 1:
ERROR: aaa is not a legal number ERROR: 9999 is not a legal number ERROR: 2.3.4 is not a legal number ERROR: 7.123 is not a legal number The average of 3 numbers is 1.38Sample Input 2:
2 aaa -9999Sample Output 2:
ERROR: aaa is not a legal number ERROR: -9999 is not a legal number The average of 0 numbers is Undefined
#include <iostream> #include <string> #include <vector> #include <cstdlib> using namespace std; int main() { string s; int n,cnt=0; double avg=0; cin>>n; for(int i=0;i<n;i++){ cin>>s; bool legal = true; bool dot_cnt = 0; for(int i=0;i<s.size();i++){ if(!(s[i]>= '0' && s[i] <= '9') && s[i] != '-' && s[i] != '.'){ 4000 legal = false; break; } if(s[i] == '.'){ if(s.size() - i > 3){ legal = false; break; } dot_cnt++; if(dot_cnt >= 2) { legal = false; break; } } } if(legal == true){ double a = (double)strtod(s.c_str(),NULL); if(a > 1000 || a<-1000){ cout<<"ERROR: "<<s<<" is not a legal number\n"; continue; } avg += a; cnt++; } else cout<<"ERROR: "<<s<<" is not a legal number\n"; } if(cnt != 0){ if(cnt == 1)printf("The average of 1 number is %.2lf\n",avg/cnt); else printf("The average of %d numbers is %.2lf\n",cnt,avg/cnt); } else cout<<"The average of 0 numbers is Undefined\n"; system("pause"); return 0; }
用strtol直接简化步骤,又做了一遍这道题发现破绽还挺多的,首先题目里没有规定.xx 或 xx.是不是合法的,还有 3e1这样的科学计数法表示的小数是不是合法的。
而下面的这种方法忽略了上面的情况也能通过。
<pre name="code" class="cpp">#include <iostream>#include <string>#include <cstdlib>using namespace std;int main(){int n,cnt = 0;cin>>n;string num;double sum = 0.0;for(int i=0;i<n;i++){cin>>num;char * pos;double value = strtod(num.c_str(),&pos);bool ok = true;if(*pos != '\0')ok = false;if(value<-1000 || value >1000)ok = false;int lpos = num.find_last_of(".");if(lpos != string::npos) if(num.size() - lpos > 3)ok = false;if(ok){cnt++;sum += value;}elseprintf("ERROR: %s is not a legal number\n",num.c_str());}if(cnt != 0){if(cnt != 1)printf("The average of %d numbers is %.2lf\n",cnt,sum/cnt);else printf("The average of 1 number is %.2lf\n",sum);}else cout<<"The average of 0 numbers is Undefined\n";return 0;}
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