欧拉项目第11题 Largest product in a grid

In the 20×20 grid below, four numbers along a diagonal line have been marked in red.
08 02 22 97 38 15 00 40 00 75 04 05 07 78 52 12 50 77 91 08

49 49 99 40 17 81 18 57 60 87 17 40 98 43 69 48 04 56 62 00

81 49 31 73 55 79 14 29 93 71 40 67 53 88 30 03 49 13 36 65

52 70 95 23 04 60 11 42 69 24 68 56 01 32 56 71 37 02 36 91

22 31 16 71 51 67 63 89 41 92 36 54 22 40 40 28 66 33 13 80

24 47 32 60 99 03 45 02 44 75 33 53 78 36 84 20 35 17 12 50

32 98 81 28 64 23 67 10 26 38 40 67 59 54 70 66 18 38 64 70

67 26 20 68 02 62 12 20 95 63 94 39 63 08 40 91 66 49 94 21

24 55 58 05 66 73 99 26 97 17 78 78 96 83 14 88 34 89 63 72

21 36 23 09 75 00 76 44 20 45 35 14 00 61 33 97 34 31 33 95

78 17 53 28 22 75 31 67 15 94 03 80 04 62 16 14 09 53 56 92

16 39 05 42 96 35 31 47 55 58 88 24 00 17 54 24 36 29 85 57

86 56 00 48 35 71 89 07 05 44 44 37 44 60 21 58 51 54 17 58

19 80 81 68 05 94 47 69 28 73 92 13 86 52 17 77 04 89 55 40

04 52 08 83 97 35 99 16 07 97 57 32 16 26 26 79 33 27 98 66

88 36 68 87 57 62 20 72 03 46 33 67 46 55 12 32 63 93 53 69

04 42 16 73 38 25 39 11 24 94 72 18 08 46 29 32 40 62 76 36

20 69 36 41 72 30 23 88 34 62 99 69 82 67 59 85 74 04 36 16

20 73 35 29 78 31 90 01 74 31 49 71 48 86 81 16 23 57 05 54

01 70 54 71 83 51 54 69 16 92 33 48 61 43 52 01 89 19 67 48

The product of these numbers is 26 × 63 × 78 × 14 = 1788696.
What is the greatest product of four adjacent numbers in the same direction (up, down, left, right, or diagonally) in the 20×20 grid?
求一条线上4个数乘机最大值
设i为x坐标，j为y坐标，从i,j 分别 左下、右、下、右下四个方向处理，i+j<=35,右下角有3*3范围的数不用处理

public static void main(String[] args){
        Integer[] arr = {
                8,02,22,97,38,15,00,40,00,75,04,05,07,78,52,12,50,77,91,8,
                49,49,99,40,17,81,18,57,60,87,17,40,98,43,69,48,04,56,62,00,
                81,49,31,73,55,79,14,29,93,71,40,67,53,88,30,03,49,13,36,65,
                52,70,95,23,04,60,11,42,69,24,68,56,01,32,56,71,37,02,36,91,
                22,31,16,71,51,67,63,89,41,92,36,54,22,40,40,28,66,33,13,80,
                24,47,32,60,99,03,45,02,44,75,33,53,78,36,84,20,35,17,12,50,
                32,98,81,28,64,23,67,10,26,38,40,67,59,54,70,66,18,38,64,70,
                67,26,20,68,02,62,12,20,95,63,94,39,63,8,40,91,66,49,94,21,
                24,55,58,05,66,73,99,26,97,17,78,78,96,83,14,88,34,89,63,72,
                21,36,23,9,75,00,76,44,20,45,35,14,00,61,33,97,34,31,33,95,
                78,17,53,28,22,75,31,67,15,94,03,80,04,62,16,14,9,53,56,92,
                16,39,05,42,96,35,31,47,55,58,88,24,00,17,54,24,36,29,85,57,
                86,56,00,48,35,71,89,07,05,44,44,37,44,60,21,58,51,54,17,58,
                19,80,81,68,05,94,47,69,28,73,92,13,86,52,17,77,04,89,55,40,
                04,52,8,83,97,35,99,16,07,97,57,32,16,26,26,79,33,27,98,66,
                88,36,68,87,57,62,20,72,03,46,33,67,46,55,12,32,63,93,53,69,
                04,42,16,73,38,25,39,11,24,94,72,18,8,46,29,32,40,62,76,36,
                20,69,36,41,72,30,23,88,34,62,99,69,82,67,59,85,74,04,36,16,
                20,73,35,29,78,31,90,01,74,31,49,71,48,86,81,16,23,57,05,54,
                01,70,54,71,83,51,54,69,16,92,33,48,61,43,52,01,89,19,67,48};
        int max = 1;
        for(int i=0;i<20;i++){//向右循环
            for(int j=0;j<20 && i+j<=35;j++){//向下循环
                if(arr[20 * j + i] == 0) {
                    continue;
                }
                if(arr[20 * j + i] == 0) {
                    continue;
                }
                int th = 1;
                if(i >= 3 && j <=16 ) {//能左斜  /
                    th = arr[20 * j + i] * arr[20 * j + i + 19] * arr[20 * j + i + 19 *2 ] * arr[20 * j + i + 19 * 3];
                    if(max < th) {
                        max =th;
                    }
                }
                if(i<=16 && j <=16) {//能右斜  /
                    th = arr[20 * j + i] * arr[20 * j + i + 21] * arr[20 * j + i + 21 *2 ] * arr[20 * j + i + 21 * 3];
                    if(max < th) {
                        max =th;
                    }
                }
                //往下
                if(j <= 16) {
                    th = arr[20 * j + i] * arr[20 * j + i + 20] * arr[20 * j + i + 20 *2 ] * arr[20 * j + i + 20 * 3];
                    if(max < th) {
                        max =th;
                    }
                }
                //往右
                if(i <= 16) {
                    th = arr[20 * j + i] * arr[20 * j + i + 1] * arr[20 * j + i + 1 *2 ] * arr[20 * j + i + 1 * 3];
                    if(max < th) {
                        max =th;
                    }
                }
                
            }
        }
        
        System.out.println(max);
    }