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217. Contains Duplicate

2016-03-09 22:47 459 查看
Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.

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//C++简单排序
class Solution {
public:
bool containsDuplicate(vector<int>& nums) {

std::sort(nums.begin(),nums.end());
for(int i=1;i<nums.size();i++)
{
if(nums[i-1]==nums[i])
return true;
}
return false;
}

};

//C++ MAP的使用
class Solution {
public:
bool containsDuplicate(vector<int>& nums) {
map<int, int> int_map;
for (int i = 0; i<nums.size(); i++) {
if(int_map.count(nums[i])){
return true;
}
int_map.insert(pair<int, int>(nums[i], i));
}
return false;
}
};

//JAVA
public class Solution {
public boolean containsDuplicate(int[] nums) {
Set<Integer>unique =new HashSet<Integer>();
for(int t:nums){
if(unique.contain(t))
return true;
else
unique.add(t);
}
return false;
}
}
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