1009. Product of Polynomials (25)
2016-03-08 17:34
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This time, you are supposed to find A*B where A and B are two polynomials.
Input Specification:
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where
K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10, 0 <= NK < ... < N2 < N1 <=1000.
Output Specification:
For each test case you should output the product of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate up to 1 decimal place.
Sample Input
Sample Output
Input Specification:
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where
K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10, 0 <= NK < ... < N2 < N1 <=1000.
Output Specification:
For each test case you should output the product of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate up to 1 decimal place.
Sample Input
2 1 2.4 0 3.2 2 2 1.5 1 0.5
Sample Output
3 3 3.6 2 6.0 1 1.6
#include<iostream> #include<stdio.h> using namespace std; int main(){ float num1[1001],num2[1001]; float rest[2001]; int i,j,n; int count=0; for(i=0;i<2001;++i){ rest[i]=0.0; } cin>>n; for(i=0;i<n;++i){ cin>>j; cin>>num1[j]; } cin>>n; for(i=0;i<n;++i){ cin>>j; cin>>num2[j]; } for(i=0;i<1001;++i){ for(j=0;j<1001;++j){ rest[i+j] += num1[i]*num2[j]; } } for(i=0;i<2001;i++){ if(rest[i]!=0) ++count; } cout<<count; for(i=2001;i>=0;--i){ if(rest[i]!=0) { cout<<" "<<i<<" "; printf("%.1f",rest[i]); } } cout<<endl; return 0; }
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