您的位置:首页 > 产品设计 > UI/UE

codeforces Longest Increasing Subsequence

2016-03-08 14:28 375 查看
Longest Increasing Subsequence

#include<iostream>
#include<cstring>
#include<string>
#include<cstdio>
#include<stdio.h>
#include<algorithm>
#include<cmath>
#include<map>
#include<queue>
#include<bitset>
#include<stack>
using namespace std;

#pragma comment(linker, "/STACK:1024000000,1024000000")
#define inf 0x3f3f3f3f
#define eps 1e-9
#define pii pair<int,int>
#define MP make_pair
#define LL  long long
#define ULL unsigned long long
#define N ( 200000 + 10 )
#define M ( 200000 + 10)
#define mod  1000000007

int c
, sz;
int a
, b
;
int s
;
int len
, cid
, pre
;
bool cmp(int a, int b) {
return a > b;
}
int findy(int rr, int v) {
int l = 1, r = rr;
while(l < r) {
int mid =( l + r>>1) + 1;
if(b[mid] <= v) l = mid;
else r = mid-1;
}
return l;
}
int main (){
int n, m;
scanf("%d", &n);
for(int i = 1; i <= n; ++i)
scanf("%d", &a[i]);
a[0] = -inf, a[++n] = inf;
for(int i = 1 ; i <= n; ++i) {
if(a[i] == -1) ++s[i];
s[i] += s[i-1];
}
scanf("%d", &m);
for(int i = 1; i <= m; ++i)
scanf("%d", &b[i]);
for(int i = 0; i <= n; ++i)
c[i] = inf;
sort(b+1, b + m + 1);
sz = 0;
for(int i = 0; i <= n; ++i) {
if(a[i] == -1) {
int kk = sz-1;
pre[i] = -1;
len[i] = -1;
for(int j = m; j >= 1; --j) {
while(kk >= 0 && c[kk] >= b[j]) --kk;
int k = kk+1;
if(k == sz) c[sz++] = b[j];
else {
c[k] = b[j];
}
cid[k] = -1;
}
}
else {
int k = lower_bound(c, c + sz, a[i]) - c;
if(k == sz) c[sz++] = a[i];
else c[k] = a[i];
cid[k] = i;
len[i] = k;
pre[i] = cid[k-1];
}
}
m = unique(b+1, b+m+1) - b - 1;
//for(int i = 0; i <= n; ++i)
//	printf("len %d pre %d\n", len[i], pre[i]);
for(int i = n, rest = m; i > 0 && rest > 0;)
if(a[i] != -1) {
if(pre[i] != -1) {
i = pre[i]; continue;
}
int y = findy(rest, a[i]-1);
//			printf(" yy %d\n", y);
for(int j = i-1; j >= 0; -- j)
if(a[j] != -1 && a[j] < a[i]) {
int x = lower_bound(b+1, b+rest+1, a[j]+1) - b ;
if(len[i] - len[j] - 1 == min(y-x+1, s[i] - s[j])) {
for(int k = j, t = x; k <= i && t <= y; ++k)
if(a[k] == -1) a[k] = b[t], b[t++] = -1;
i = j;
rest = x - 1;
break;
}
}
}
for(int i = 1, j = 1; i < n; ++i) if(a[i] == -1) {
while(b[j] == -1) ++j;
a[i] = b[j++];
}
for(int i = 1 ;i < n; ++i)
printf("%d%c", a[i], i == n-1 ? '\n': ' ');
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: