将字符串s1中的任何与字符串s2中字符匹配的字符都删除

编写一个程序，将字符串s1中的任何与字符串s2中字符匹配的字符都删除。函数原型：void my_squeeze(char s1[], char s2[])#include <stdio.h>void my_squeeze(char s1[], char s2[]){int i = 0;int j = 0;while (s2[j]){while(s1[i]){if (s2[j]==s1[i]){while (s1[i+1]){s1[i] = s1[i + 1];i++;}s1[i] = '\0';}i++;}i = 0;j++;}}int main(){char arr1[] = "qwdcgje";char arr2[] = "abcdefg";/*char arr1[] = { 'q', 'w', 'd', 'c', 'g', 'j', 'e' };char arr2[] = { 'a', 'b', 'c', 'd', 'e', 'f' }; 字符数组后面没有0，不知道什么时候停下，所以出错*/my_squeeze(arr1, arr2);printf("%s\n", arr1);system("pause");return 0;}