86. Partition List LeetCode
2016-03-07 22:38
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题意:给出一个链表和一个元素x,把链表中节点值小于x的都放在链表左边,大于x的都放在右边。
题解:开两个头节点,扫一遍原链表,小于x的链接到第一个头,大于x的链接到第二个头,最后把两个链接一下。
题解:开两个头节点,扫一遍原链表,小于x的链接到第一个头,大于x的链接到第二个头,最后把两个链接一下。
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* partition(ListNode* head, int x) { ListNode* head1 = new ListNode(0),*head2 = new ListNode(0),*pd1,*pd2; head1->next = head2->next =head; pd1 = head1,pd2 = head2; while(head) { if(head->val < x) { pd1->next = head; pd1 = pd1->next; } else { pd2->next = head; pd2 =pd2->next; } head = head->next; } pd2->next = NULL; pd1->next = head2->next; return head1->next; } };
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