您的位置:首页 > 产品设计 > UI/UE

[LeetCode]96. Unique Binary Search Trees

2016-03-07 10:06 471 查看
Given n, how many structurally unique BST's (binary search trees) that store values 1...n?

For example,

Given n = 3, there are a total of 5 unique BST's.
1         3     3      2      1
\       /     /      / \      \
3     2     1      1   3      2
/     /       \                 \
2     1         2                 3


思路:采用动态规划,n = 0,1一种结果
n = 2 时,两种情况,根节点占一个,左1右0,左0右1;
n = 3时, 三种情况,根节点占一个,左2右0,左1右1,左0右2;
……
public int numTrees(int n) {
int[] dp = new int[n+1];
dp[0] = 1;
for (int i=1; i<=n; i++) {
//int sum = 0;
for (int j=1;j<=i;j++) {
dp[i] += dp[j-1] * dp[i-j];
}
//dp[i] = sum;
}
return dp
;
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: