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leetcode268 Missing Number

2016-03-05 11:20 357 查看

268. Missing Number

Total Accepted:
41297
Total Submissions:
104911
Difficulty: Medium
Given an array containing n distinct numbers taken from
0, 1, 2, ..., n
, find the one that is missing from the array.

For example,

Given nums =
[0, 1, 3]
return
2
.

Note:

Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?

解法一:

class Solution {
public:
int missingNumber(vector<int>& nums) {
int k = 0;
sort(nums.begin(), nums.end());
for (auto i : nums)
{
if (i != k)
return k;
++k;
}
return k;
}
};


解法二:

class Solution {
public:
int missingNumber(vector<int>& nums) {
int k = 0;
int ans = 0;
for (int i : nums) {
ans += k++ - i;
}
return ans + k;
}
};
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