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PAT-A1025 PAT Ranking(25)

2016-03-01 10:16 459 查看
重点是排名,方法:排序好后第一个人是第一名,其后则如果和前一个分数一样,则和前一个人排名一样,否则排名为下标+1.

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
using namespace std;

#define MAX 30000+10
struct Testee
{
char regis_num[14];
int score;
int final_rank;
int locata_number;
int local_rank;

} testee[MAX];
int cnt = 0;

int cmp_local(const void *a, const void *b)
{
return (*(Testee*)b).score - (*(Testee*)a).score;
}

int cmp_all(const void *a, const void *b)
{
if ((*(Testee*)b).score != (*(Testee*)a).score)
return (*(Testee*)b).score - (*(Testee*)a).score;
else
return strcmp((*(Testee*)a).regis_num, (*(Testee*)b).regis_num);
}

int main()
{
//freopen("in.txt", "r", stdin);
//freopen("out.txt", "w", stdout);
int N = 0;
cin >> N;

//n个地点
for (int i = 1; i <= N; i++)
{
int n = 0;
Testee local_testee[300+10];
cin >> n;
for (int j = 0; j < n; j++)
{
cin >> local_testee[j].regis_num >> local_testee[j].score;
local_testee[j].locata_number = i;
}
qsort(local_testee, n, sizeof(local_testee[0]), cmp_local);

local_testee[0].local_rank = 1;
testee[cnt++] = local_testee[0];
for (int j = 1; j < n; j++)
{
if (local_testee[j].score == local_testee[j-1].score)
local_testee[j].local_rank = local_testee[j-1].local_rank;
else
local_testee[j].local_rank = j+1;

testee[cnt++] = local_testee[j];
}
}

qsort(testee, cnt, sizeof(testee[0]), cmp_all);
testee[0].final_rank = 1;
for (int i = 1; i < cnt; i++)
{
if (testee[i].score == testee[i-1].score)
testee[i].final_rank = testee[i-1].final_rank;
else
testee[i].final_rank = i+1;
}

//output
cout << cnt << endl;
for (int i = 0; i < cnt; i++)
{
cout << testee[i].regis_num << " " << testee[i].final_rank << " "
<< testee[i].locata_number << " " << testee[i].local_rank << endl;
}
return 0;
}
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