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Compare Version Number

2016-02-29 21:26 465 查看
package cn.edu.xidian.sselab.string;

/**
*
* @author zhiyong wang
* title: Compare Version Numbers
* content:
* Compare two version numbers version1 and version2.
* If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
*
* You may assume that the version strings are non-empty and contain only digits and the . character.
* The . character does not represent a decimal point and is used to separate number sequences.
* For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
*
* Here is an example of version numbers ordering:
*
* 0.1 < 1.1 < 1.2 < 13.37
*
*/
public class CompareVersionNumbers {

//参考大牛的做法,这个题首先分裂,然后求出两个数组长度的最大值,用这个大的值进行遍历,如果当前值小于自己的长度,就用自己的值,否则是0,这样进行判断
public int compareVersion(String version1, String version2){
String[] v1 = version1.split("\\.");
String[] v2 = version2.split("\\.");
int max = v1.length <= v2.length ? v2.length : v1.length;
for(int i=0;i<max;i++){
Integer vv1 = i < v1.length ? Integer.valueOf(v1[i]) : 0;
Integer vv2 = i < v2.length ? Integer.valueOf(v2[i]) : 0;
if(vv1 > vv2) return 1;
else if(vv1 < vv2) return -1;
}
return 0;
}
}
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