数字转换成字符串

#include <iostream>
#define MAX 200
using namespace std;
int ltoAandRepeat(unsigned int num)
{
char p1[MAX], p[MAX];
int count = 0;
int temp = num;
//计算整数num几位数
while (temp > 0)
{
temp /= 10;
count++;
}
//整数转换成字符串
temp = num;
int i;
for (i = 0; i < count; i++)
{
p1[i] = temp % 10+'0';
temp /= 10;
}
for (i = 0; i < count; i++)
{
p[count - 1 - i] = p1[i];
}
p[count] = '\0';
cout << p<<endl;

//判断有无重复字符串
int n = 0;
int j;
for (i = 0; i < count - 1; i++)
{
for (j = i + 1; j < count; j++)
{
if (p[i] == p[j]&&j>=i+2)	//不允许有重复的，如111不被认为是重复字符串
// 如果允许，则if(p[i]==p[j])即可
{
if (p[++i] == p[++j])
return 1;
}
}
}
return 2;
}

int main()
{
int num;
cin >> num;
cout << ltoAandRepeat(num) << endl;
cin.get();
cin.get();
}

#include <iostream>
using namespace std;
#define MAX 200
int ltoAandRepeat(unsigned int theNum, char*s)
{
char str[MAX];
char Repeat[MAX];
int interg, remainder, i = 0, j , z = 0, k = 0, temp;
//数字转换成字符串
remainder = theNum % 10;
interg = theNum / 10;
while (interg)
{
str[i] = remainder + 48;
i++;
remainder = interg % 10;
interg = interg / 10;
}
str[i] = remainder + 48;
i++;
str[i] = '\0';
for (z = 0, j = i - 1; j >= 0; j--, z++)
{
s[z] = str[j];
}
s[z] = '\0';
cout << theNum<<" has been transferred into a string: "<<s<<endl;

for (i = 0; s[i] != '\0'; i++)// 判断有无重复字符串
{
for (j = 0; j < i; j++)// 判断之前是否出现过该字符
{
if (s[j] == s[i])// 若出现过，则从此位置开始向后判断有多少位重复
{
z = i;
z++;
j++;
temp = 1;
while (s[j] == s[z] && s[z] != '\0')// 实现可重叠的重复字符串
// 实现无重叠的重复字符串，用while(s[j]==s[z]&&s[z]!='\0'&&j<i)
{
z++;
j++;
temp++;
}
if (temp > 1)
{
for (k = 0; k < temp; k++,i++)
{
Repeat[k] = s[i];
}
Repeat[k] = '\0';
cout << s << " has duplicated sub-string(s), which is " << Repeat << endl;
return 1;
}
}
}
}
return 2;
}

int main()// 主函数
{
int number, temp1, re;
char s[MAX];
//	temp1=(cin >> number);
temp1 = scanf("%d", &number);
while (temp1 == 1)// 结束标志是EOF，即按Ctrl+C
{
re = ltoAandRepeat(number, s);
cout << re << endl;
printf("Please enter the next number: ");
temp1 = scanf("%d", &number);
}
return 0;
}