New Year and Days
2016-02-26 16:09
375 查看
Description
Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming year 2016.
Limak wants to prove how responsible a bear he is. He is going to regularly save candies for the entire year 2016! He considers various saving plans. He can save one candy either on some fixed day of the week or on some fixed day of the month.
Limak chose one particular plan. He isn't sure how many candies he will save in the 2016 with his plan. Please, calculate it and tell him.
Input
The only line of the input is in one of the following two formats:
"x of week" where
x (1 ≤ x ≤ 7) denotes the day of the week. The 1-st day is Monday and the 7-th one is Sunday.
"x of month" where
x (1 ≤ x ≤ 31) denotes the day of the month.
Output
Print one integer — the number of candies Limak will save in the year 2016.
Sample Input
Input
Output
Input
Output
Sample Output
Hint
Polar bears use the Gregorian calendar. It is the most common calendar and you likely use it too. You can read about it on Wikipedia if you want to –
https://en.wikipedia.org/wiki/Gregorian_calendar. The week starts with Monday.
In the first sample Limak wants to save one candy on each Thursday (the 4-th day of the week). There are
52 Thursdays in the 2016. Thus, he will save
52 candies in total.
In the second sample Limak wants to save one candy on the 30-th day of each month. There is the 30-th day in exactly
11 months in the 2016 — all months but February. It means that Limak will save
11 candies in total.
Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming year 2016.
Limak wants to prove how responsible a bear he is. He is going to regularly save candies for the entire year 2016! He considers various saving plans. He can save one candy either on some fixed day of the week or on some fixed day of the month.
Limak chose one particular plan. He isn't sure how many candies he will save in the 2016 with his plan. Please, calculate it and tell him.
Input
The only line of the input is in one of the following two formats:
"x of week" where
x (1 ≤ x ≤ 7) denotes the day of the week. The 1-st day is Monday and the 7-th one is Sunday.
"x of month" where
x (1 ≤ x ≤ 31) denotes the day of the month.
Output
Print one integer — the number of candies Limak will save in the year 2016.
Sample Input
Input
4 of week
Output
52
Input
30 of month
Output
11
Sample Output
Hint
Polar bears use the Gregorian calendar. It is the most common calendar and you likely use it too. You can read about it on Wikipedia if you want to –
https://en.wikipedia.org/wiki/Gregorian_calendar. The week starts with Monday.
In the first sample Limak wants to save one candy on each Thursday (the 4-th day of the week). There are
52 Thursdays in the 2016. Thus, he will save
52 candies in total.
In the second sample Limak wants to save one candy on the 30-th day of each month. There is the 30-th day in exactly
11 months in the 2016 — all months but February. It means that Limak will save
11 candies in total.
#include <stdio.h> #include <string.h> #include <math.h> int main() { int n, m, P, Q, i, x, y; char a[5], b[5]; scanf("%d", &n); scanf("%s", a); scanf("%s", b); if (b[0] == 'w') { if (n == 5 || n == 6) printf("53\n"); else printf("52\n"); } if (b[0] == 'm') { if (n == 30) printf("11\n"); else if (n == 31) printf("7\n"); else printf("12\n"); } return 0; }
相关文章推荐
- python处理txt文件
- PAT (Basic Level)1022. D进制的A+B
- Eclipse web项目导入到myeclipse中Tomcat不能直接部署解决方法
- Android逆向分析基础-Android可执行文件
- 本地通知
- protobuf 参考资料
- ecshop登录
- 基于Spring的app后台开源框架
- iOS实战-自定义的横向滚动控件CustomScrollView
- Uva1368
- 关于python的类方法、实例方法和静态方法区别
- sleep在windows下和linux的不同
- tableView崩溃问题
- NYOJ 303-序号互换【模拟】
- Python学习笔记 - 3.函数
- java中XML格式的字符串4读取方式的简单比较
- neutron的基本原理
- Android启动过程分析——init.c(一)
- 数据结构-6
- 客户端登录提示 :拒绝访问Temp目录解决方法