https://projecteuler.net/problem=6

Sum square difference

Problem 6

The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

太简单了，都没有解释的必要result = 0
sumrange = sum(range(1,101))
for i in range(1,101):
result += i * (sumrange - i)

print(result)