hdu 2612 简单搜索

[code]#include<stdio.h>
#include<string.h>
int n,m;
struct node
{
    int x;
    int y;
}Y,M,kfc[40010];
char map[210][210];
int queue[100010];
int way[210][210];
int kfctime[40010];
int move[4][2]={{1,0},{-1,0},{0,-1},{0,1}};
int min(int g,int h)
{
    return g>h?h:g;
}
void bfs(int x,int y)
{
    int front=0;
    int end=0;
    queue[end++]=x;
    queue[end++]=y;
    memset(way,-1,sizeof(way));
    way[x][y]=0;
    while(front!=end)
    {
        int oldx=queue[front++];
        int oldy=queue[front++];
        for(int i=0;i<4;i++)
        {
            int newx=oldx+move[i][0];
            int newy=oldy+move[i][1];
            if(newx>=0&&newx<n&&newy>=0&&newy<m&&map[newx][newy]!='#'&&way[newx][newy]==-1)
            {
                way[newx][newy]=way[oldx][oldy]+1;
                queue[end++]=newx;
                queue[end++]=newy;
            }
        }
    }
}
int main()
{
    while(scanf("%d%d",&n,&m)!=EOF)
    {
        int cin=0;
        int i,j;
        for(i=0;i<n;i++)
        {
            scanf("%s",map[i]);
            for(j=0;j<m;j++)
            {
                if(map[i][j]=='Y')
                {
                    Y.x=i;
                    Y.y=j;
                }
                if(map[i][j]=='M')
                {
                    M.x=i;
                    M.y=j;
                }
                if(map[i][j]=='@')
                {
                    kfc[cin].x=i;
                    kfc[cin].y=j;
                    cin++;
                }
            }
        }
        bfs(Y.x,Y.y);
        memset(kfctime,0,sizeof(kfctime));
        for(i=0;i<cin;i++)
        {
            if(way[kfc[i].x][kfc[i].y]==-1)
                kfctime[i]=0x3f3f3f3f;
            else
                kfctime[i]=way[kfc[i].x][kfc[i].y];
        }
        bfs(M.x,M.y);
        int ans=0x3f3f3f3f;
        for(i=0;i<cin;i++)
        {
            if(way[kfc[i].x][kfc[i].y]!=-1)
            {
                ans=min(ans,kfctime[i]+way[kfc[i].x][kfc[i].y]);
            }
        }
        printf("%d\n",11*ans);
    }
    return 0;
}