mysql 时间差问题集锦
2016-02-19 17:32
555 查看
SELECT * from grouptoadd where taskid = '103244';
select datediff(max(spreadtime),min(createtime)) from grouptoadd where taskid = '103244';
-- 【mysql】时间差
SELECT TIMESTAMPDIFF(DAY, createtime ,spreadtime) AS `DAY` from grouptoadd where taskid = '103244';
SELECT TIMESTAMPDIFF(HOUR, createtime ,spreadtime) AS `HOUR` from grouptoadd where taskid = '103244';
SELECT TIMESTAMPDIFF(MINUTE, createtime ,spreadtime) AS `MINUTE` from grouptoadd where taskid = '103244';
SELECT TIMESTAMPDIFF(SECOND, createtime ,spreadtime) AS `Second` from grouptoadd where taskid = '103244';
相关文章推荐
- mysql数据优化方案
- MySql命令
- innodb快照读取
- 错误 1130: Host '***.***.***.***' is not allowed to connect to this MySQL
- c3p0连接池maxIdleTime小于mysql数据库interactive_timeout参数导致出现NewPooledConnection close Exception的解决办法
- Mysql避免全表扫描sql查询优化
- MySQL几个函数学习
- MySQL-InnoDB Compact 行记录格式
- 如何设计高效合理的MySQl查询语句
- WIN7下MYSQL的非安装版解压安装方法
- 64位MYSQL5.6安装配置
- Mysql详解之锁
- MySQL索引原理与慢查询优化
- 读取逗号分隔的字符串并逐条插入表mysql
- MySQL无法连接[MySql Host is blocked because of many connection errors]
- mysql max_allowed_packet 设置过小导致记录写入失败
- 安装unixODBC安装连接mysql
- Ubuntu中MySQL数据库安装
- Mysql-5.7.10启动失败 。
- MySQL中有关icp mrr和bka的特性