109. Convert Sorted List to Binary Search Tree LeetCode
2016-02-16 19:22
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题意:把排序好的链表转换成二叉搜索树。
题解:和把排序好的数组转换成二叉搜索树是一个思路,每次从中间分开。这里用slow和fast去找链表的中间节点。
题解:和把排序好的数组转换成二叉搜索树是一个思路,每次从中间分开。这里用slow和fast去找链表的中间节点。
class Solution { public: TreeNode* sortedListToBST(ListNode* head) { if(head == NULL) return NULL; if(head->next == NULL) { return new TreeNode(head->val); } ListNode *fast = head->next->next, *slow = head; while(fast && fast->next) { fast = fast->next->next; slow = slow->next; } ListNode *temp = slow->next; TreeNode *ans = new TreeNode(temp->val); slow->next = NULL; ans->left = sortedListToBST(head); ans->right = sortedListToBST(temp->next); return ans; } };
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