1054. The Dominant Color (20)
2016-02-15 10:04
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Behind the scenes in the computer's memory, color is always talked about as a series of 24 bits of information for each pixel. In an image, the color with the largest proportional area is called the dominant color. A strictly dominant color takes more
than half of the total area. Now given an image of resolution M by N (for example, 800x600), you are supposed to point out the strictly dominant color.
Input Specification:
Each input file contains one test case. For each case, the first line contains 2 positive numbers: M (<=800) and N (<=600) which are the resolutions of the image. Then N lines follow, each contains M digital colors in the range [0, 224).
It is guaranteed that the strictly dominant color exists for each input image. All the numbers in a line are separated by a space.
Output Specification:
For each test case, simply print the dominant color in a line.
Sample Input:
Sample Output:
这种方法只能当某个元素超过总元素数量一半时找到的结果才正确,而不是寻找里面有最多数量的元素,不要搞混了。
than half of the total area. Now given an image of resolution M by N (for example, 800x600), you are supposed to point out the strictly dominant color.
Input Specification:
Each input file contains one test case. For each case, the first line contains 2 positive numbers: M (<=800) and N (<=600) which are the resolutions of the image. Then N lines follow, each contains M digital colors in the range [0, 224).
It is guaranteed that the strictly dominant color exists for each input image. All the numbers in a line are separated by a space.
Output Specification:
For each test case, simply print the dominant color in a line.
Sample Input:
5 3 0 0 255 16777215 24 24 24 0 0 24 24 0 24 24 24
Sample Output:
24
这种方法只能当某个元素超过总元素数量一半时找到的结果才正确,而不是寻找里面有最多数量的元素,不要搞混了。
#include <iostream> #include <vector> using namespace std; int main() { int m,n; cin>>m>>n; vector<int> image(m*n); for(int i=0;i<n*m;i++) { cin>>image[i]; } int candidate=-1,count=0; for(int i=0;i<m*n;i++) { if(count == 0) { candidate=image[i]; count++; } else { if(candidate != image[i]) count--; else count++; } } cout<<candidate<<endl; return 0; }
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