1031. Hello World for U (20)
2016-02-12 22:32
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Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, "helloworld" can be printed as:
That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1 characters,
then left to right along the bottom line with n2 characters,
and finally bottom-up along the vertical line with n3 characters.
And more, we would like U to be as squared as possible -- that is, it must be satisfied that n1 =
n3 =
max { k| k <= n2 for
all 3 <= n2 <=
N } with n1 +
n2 +
n3 -
2 = N.
Input Specification:
Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.
Output Specification:
For each test case, print the input string in the shape of U as specified in the description.
Sample Input:
Sample Output:
h d e l l r lowo
That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1 characters,
then left to right along the bottom line with n2 characters,
and finally bottom-up along the vertical line with n3 characters.
And more, we would like U to be as squared as possible -- that is, it must be satisfied that n1 =
n3 =
max { k| k <= n2 for
all 3 <= n2 <=
N } with n1 +
n2 +
n3 -
2 = N.
Input Specification:
Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.
Output Specification:
For each test case, print the input string in the shape of U as specified in the description.
Sample Input:
helloworld!
Sample Output:
h ! e d l l lower
确定各段的长度的方法见代码
#include <iostream> #include <string> #include <queue> using namespace std; int main() { string str; cin >> str; deque<char> que(str.begin(), str.end()); int n1, n2, n3; n1 = n2 = n3 = (str.size()+2) / 3; int add = (str.size()+2) % 3; switch (add) { case 0: break; case 1: n2=n2 + 1; break; case 2: n2=n2 + 2; break; case 3: n2=n2 + 1; n1=n1 + 1; n3=n3 + 1; break; } string space(n2 - 2, ' '); for (int i = 0; i < n1-1; i++) { cout << que.front(); que.pop_front(); cout << space; cout << que.back()<<endl; que.pop_back(); } while (que.empty() == false) { cout<<que.front(); que.pop_front(); } cout << endl; system("pause"); return 0; }
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