杭电1060 Leftmost Digit

Leftmost Digit

2
3
4

2
2

Hint
In the first case, 3 * 3 * 3 = 27, so the leftmost digit is 2.
In the second case, 4 * 4 * 4 * 4 = 256, so the leftmost digit is2这个n^n很大，所以考虑用对数求，假设a为n^n的最左为，n^n=a*10^m,两边取对数n*lgn=m+lga;a=10^(n*lgn-m),可以看出m为n*lgn的整数部分，所以可以使用强制转由你n*lgn得到m[code]#include<stdio.h>
#include<math.h>
int main()
{
int a,t;
long long n;
double s;
scanf("%d",&t);
while(t--)
{
scanf("%lld",&n);
s=n*log10(n);
a=1*pow(10,s-(long long)s);
printf("%d\n",a);
}
return 0;
}