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基于xml配置springmvc

2016-01-26 16:14 375 查看
controller关键代码

public class MenuController extends MultiActionController


方法:

public ModelAndView list(HttpServletRequest request,
HttpServletResponse response)
{
CoreMenuQuery query = new CoreMenuQuery();
List<CoreMenu> list = coreMenuService.find(query);
return new ModelAndView("index");
}


一定要

HttpServletRequest request,
HttpServletResponse response


xml配置

<bean id="paraMethodResolver"
class="org.springframework.web.servlet.mvc.multiaction.ParameterMethodNameResolver">
<property name="paramName" value="action"/>
<property name="defaultMethodName" value="list"/>
</bean>
<!-- 页面View层基本信息设定 -->
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>
<property name="prefix" value="/WEB-INF/content/"/>
<property name="suffix" value=".jsp"/>
</bean>
<!-- servlet映射列表,所有控制层Controller的servlet在这里定义 -->
<bean id="urlMapping"
class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="mappings">
<props>
<prop key="/admin/index.htm">adminController</prop>
<prop key="/menu/index.htm">adminController</prop>
</props>
</property>
</bean>

<bean id="adminController" class="com.core.action.AdminController">
</bean>


访问方式类似
http://localhost:8080/BaseS2I/menu/index.htm?action=list
action来自
<property name="paramName" value="action"/>
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