您的位置:首页 > 职场人生

leetcode之Minimum Depth of Binary Tree

2016-01-23 19:35 429 查看
题目:

Given a binary tree, find its minimum depth.

The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.

解答:

很简单的DFS,可以加入一个剪枝

/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
void DFS(TreeNode *root,int cur)
{
if(cur + 1> minDep)
return;
if(root->left == NULL && root->right == NULL)
{
if(cur + 1 < minDep)
minDep = cur + 1;
return;
}
if(root->left != NULL)
DFS(root->left,cur + 1);
if(root->right != NULL)
DFS(root->right, cur + 1);
}
int minDepth(TreeNode* root) {
minDep = 1 << 30;
if(root == NULL)
return 0;
DFS(root,0);
return minDep;
}
private:
int minDep;
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签:  leetcode 面试 算法