点击两次退出应用

public boolean onKeyDown(int keyCode, KeyEvent event){

if(keyCode == KeyEvent.KEYCODE_BACK && event.getAction() == KeyEvent.ACTION_DOWN){

if((System.currentTimeMillis()-exitTime) > 2000){
Toast.makeText(getApplicationContext(), "再按一次退出程序", Toast.LENGTH_SHORT).show();
exitTime = System.currentTimeMillis();
}
else{
finish();
System.exit(0);
}
return true;
}
return super.onKeyDown(keyCode, event);
}