抓狂的c++错误:...which is of non-class type..

代码如下：

//sqlite_interface.h
class SqlteOp {
private:
sqlite3 *db;

public:
SqlteOp(string dbname);
~SqliteOp();
void print();
}

//sqlite_interface.cpp
SqliteOp::SqliteOp(string dbname)
{
cout<<"db name is: "<<dbname<<endl;
sqlite3_open(dbname.c_str(), &db);
...
}

SqliteOp::print()
{
cout<<"Sqlite Operation print function"<<endl;
...
}
SqliteOp::~SqliteOp()
{
cout<<"destroy sqlite op object"<<endl;
sqlite3_close(db);
}

//main.cpp
int main(int argc, char **argv)
{
SqliteOp sqliteOp(string(argv[1]));
sqliteOp.print();
return 0;
}

//编译
dk@dkos:~ g++ --std=c++11 main.cpp sqlinteop.cpp -I /usr/local/include -L /usr/local/lib -lsqlite3 -lpthread -ldl

//报错
main.cp:14:13: error: request for member 'print' in 'sqliteOp', which is of non-class type.......

恶心，非常恶心，这种错误太古怪了，让人觉得这语言太难用了，话费的编译调试成本也太大了….，无语了，看解决方法，将g++贴换成clang++尝试编译（为什么用clang，因为clang能打印出更好的错误提示信息)，看具体提示

dk@dkos:~ clang++ --std=c++11 main.cpp sqlinteop.cpp -I /usr/local/include -L /usr/local/lib -lsqlite3 -lpthread -ldl
//提示如下
main.cpp:14:23: note: add a pair of parentheses to declare a variable
SqliteOp sqliteOp(string(argv[1]));
^
(                )

按照提示加上之后编译通过，我猜可能编译器把这个定义只当做了函数声明，而没有把它当做一个类的定义。

类似问题后来我google一下发现有人也撞上了，但是他（她）解释的更清楚一些，链接如下

http://dehun.bitbucket.org/articles/23_oct_2013-Error%20which%20is%20of%20non-class%20type.html