Poj 2676 Sudoku
2016-01-14 15:35
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Sudoku
Description
Sudoku is a very simple task. A square table with 9 rows and 9 columns is divided to 9 smaller squares 3x3 as shown on the Figure. In some of the cells are written decimal digits from 1 to 9. The other cells are empty. The goal is to fill the empty cells with
decimal digits from 1 to 9, one digit per cell, in such way that in each row, in each column and in each marked 3x3 subsquare, all the digits from 1 to 9 to appear. Write a program to solve a given Sudoku-task.
Input
The input data will start with the number of the test cases. For each test case, 9 lines follow, corresponding to the rows of the table. On each line a string of exactly 9 decimal digits is given, corresponding to the cells in this line. If a cell is empty
it is represented by 0.
Output
For each test case your program should print the solution in the same format as the input data. The empty cells have to be filled according to the rules. If solutions is not unique, then the program may print any one of them.
Sample Input
Sample Output
Source
Southeastern Europe 2005
思路:纯暴力的dfs搜索,对0,也就是还没有数字的格子进行判断,可以就继续下一个格子,不行就换数字,再不行就回溯,不过
这里要注意,如果遍历整个图的话,会超时,所以只需要记录下空格的就行了。
AC代码如下:
Time Limit: 2000MS | Memory Limit: 65536K | |||
Total Submissions: 16554 | Accepted: 8075 | Special Judge |
Sudoku is a very simple task. A square table with 9 rows and 9 columns is divided to 9 smaller squares 3x3 as shown on the Figure. In some of the cells are written decimal digits from 1 to 9. The other cells are empty. The goal is to fill the empty cells with
decimal digits from 1 to 9, one digit per cell, in such way that in each row, in each column and in each marked 3x3 subsquare, all the digits from 1 to 9 to appear. Write a program to solve a given Sudoku-task.
Input
The input data will start with the number of the test cases. For each test case, 9 lines follow, corresponding to the rows of the table. On each line a string of exactly 9 decimal digits is given, corresponding to the cells in this line. If a cell is empty
it is represented by 0.
Output
For each test case your program should print the solution in the same format as the input data. The empty cells have to be filled according to the rules. If solutions is not unique, then the program may print any one of them.
Sample Input
1 103000509 002109400 000704000 300502006 060000050 700803004 000401000 009205800 804000107
Sample Output
143628579 572139468 986754231 391542786 468917352 725863914 237481695 619275843 854396127
Source
Southeastern Europe 2005
思路:纯暴力的dfs搜索,对0,也就是还没有数字的格子进行判断,可以就继续下一个格子,不行就换数字,再不行就回溯,不过
这里要注意,如果遍历整个图的话,会超时,所以只需要记录下空格的就行了。
AC代码如下:
#include <iostream> #include <cstring> using namespace std; const int maxn=15; int mp[maxn][maxn]; bool ok=false; struct Node{ int x,y; }q[maxn*maxn]; int cnt=0; bool safe(int i,int cn){ // if(mp[x][y]) return false; int x=q[cn].x,y=q[cn].y; for(int j=0;j<9;j++) if(mp[x][j]==i) return false; for(int j=0;j<9;j++) if(mp[j][y]==i) return false; int tx=x/3; int ty=y/3; for(int j=(tx)*3;j<(tx)*3+3;j++){ for(int k=(ty)*3;k<(ty)*3+3;k++) if(mp[j][k]==i) return false; } return true; } void show(){ for(int i=0;i<9;i++){ for(int j=0;j<9;j++) cout<<mp[i][j]; cout<<endl; } } void dfs(int cn){ if(ok) return ; if(cn<0){ ok=true; show(); return ; } int x=q[cn].x,y=q[cn].y; for(int i=1;i<=9;i++){ if(safe(i,cn)){ mp[x][y]=i; if(ok) return ; dfs(cn-1); } } if(ok) return ; mp[x][y]=0;return ; } int main(){ int t; cin>>t; while(t--){ ok=false; cnt=0; memset(mp,0,sizeof(mp)); for(int i=0;i<9;i++){ for(int j=0;j<9;j++){ char xx; cin>>xx; mp[i][j]=xx-'0'; if(mp[i][j]==0){ Node tmp; tmp.x=i,tmp.y=j; q[cnt++]=tmp; } } } dfs(cnt-1); } return 0; }
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