1.找出字符串中出现的次数；2.利用循环去除空格。3.字符串以什么结尾

package guoguo;

public class Number {

public static void main(String[] args) {
// TODO Auto-generated method stub

String s="mingrikejijavabu";

/*System.out.println("s的长度是："+s.length());

System.out.println("s的截取一次是"+s.substring(0,4));

System.out.println("s的截取二次是"+s.substring(4,8));

System.out.println("s的截取三次是"+s.substring(8,16));*/

char as[]=s.toCharArray();

int cs=0;

for (int i=0;i<s.length();i++)
{
if (as[i]=='i')
{
cs+=1;
}

}
System.out.println("cs="+cs);

//用for和if循环去除空格
String str1 = "mi ngri keji ja v a bu";

String[] str2 = str1.split("");

String str3 = "";

for(int j = 0; j < str2.length; j++) {

if(str2[j].equals(" ")) {

}

else {

str3 += str2[j];

//str3 = str3 + str2[j];

}

}

System.out.println("原来的字符串为: "+str1);

System.out.println("去空格之后的字符串为: "+str3);

//题目：自己 判断是以什么结束的

String w="wiwokkxbgttdduns";

boolean c=w.endsWith("s");

if (c);
{
System.out.println("字符串w是以s结尾的");
}

}
}