leetcode205---Isomorphic Strings(相同结构的字符串)
2016-01-11 15:01
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问题描述:
Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Note:
You may assume both s and t have the same length.
问题求解:利用两个hash表
Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg", "add", return true. Given "foo", "bar", return false. Given "paper", "title", return true.
Note:
You may assume both s and t have the same length.
问题求解:利用两个hash表
class Solution { public: bool isIsomorphic(string s, string t) { unordered_map<char, int> um1; unordered_map<char, int> um2; for(int i=0;i<s.length();i++) {//hash映射.如"egg", "add",相同位置处字母索引相同 //对于每个字符串,相同字母对应的索引累加。 um1[s[i]] += i+1; um2[t[i]] += i+1; }//若字符串结构相同,则每个字符对应hash映射也应相同 for(int j=0;j<s.length();j++) { if(um1[s[j]] != um2[t[j]]) return false; } return true; } };
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