232. Implement Queue using Stacks
2015-12-23 22:00
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Implement the following operations of a queue using stacks.
push(x) – Push element x to the back of queue.
pop() – Removes the element from in front of queue.
peek() – Get the front element.
empty() – Return whether the queue is empty.
Notes:
You must use only standard operations of a stack – which means only push to top, peek/pop from top, size, and is empty operations are valid.
Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
用st1保存入队的数。
用st2来删除出队的数,此时为保证入队顺序来显示队头,需要逆序,此时st1就为空。
用st2.empty做标记,来记录是否进行过逆序操作。
push(x) – Push element x to the back of queue.
pop() – Removes the element from in front of queue.
peek() – Get the front element.
empty() – Return whether the queue is empty.
Notes:
You must use only standard operations of a stack – which means only push to top, peek/pop from top, size, and is empty operations are valid.
Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
用st1保存入队的数。
用st2来删除出队的数,此时为保证入队顺序来显示队头,需要逆序,此时st1就为空。
用st2.empty做标记,来记录是否进行过逆序操作。
class Queue { public: // Push element x to the back of queue. void push(int x) { while(!st2.empty()) { st1.push(st2.top()); st2.pop(); } st1.push(x); } // Removes the element from in front of queue. void pop(void) { while(!st1.empty()) { st2.push(st1.top()); st1.pop(); } st2.pop(); } // Get the front element. int peek(void) { while(!st1.empty()) { st2.push(st1.top()); st1.pop(); } return st2.top(); } // Return whether the queue is empty. bool empty(void) { return st1.empty() && st2.empty(); } private: stack<int> st1; stack<int> st2; };
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