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随机数的产生--随机文本串的生成

2015-12-21 21:48 435 查看
数字的产生,字符串的随机生成,直接贴代码了

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
#include <iostream>
#include <string>
#include <vector>

#define N 10240

int main(int argc, char *argv[])
{
if(argc < 3)
{
printf("Usage : %s infile outfile\n", argv[0]);
exit(-1);
}
FILE *fp_in, *fp_out;
fp_in = fopen(argv[1], "rb");
fp_out = fopen(argv[2], "wb");
if(NULL == fp_in || NULL == fp_out)
{
printf("Open file wrong!\n");
exit(-1);
}

char numDic[11]
;
int i = 0;
for( i = 0; i < 11; ++ i)
memset(numDic[i], 0, N);

char buf
;
char *p1 = NULL, *p2 = NULL;
int len = 0;
int cnt = 0;
while(fgets(buf, N, fp_in))
{
len = strlen(buf);
while('\t' == buf[len - 1] || ' ' == buf[len - 1] || '\n' == buf[len - 1])
-- len;
buf[len] = '\0';
p1 = &buf[0];
p2 = strrchr(p1, '|');
while(p2)
{
*p2 = '\0';
++ p2;
strcpy(numDic[cnt ++], p2);
p2 = strrchr(p1, '|');
}
strcpy(numDic[cnt ++], p1);
}

int arr1[1000], arr2[100];
srand( (unsigned)time(NULL) );
for(i = 0; i < 1000; ++ i)
arr1[i] = rand() % 10;
for(i = 0; i < 100; ++ i)
arr2[i] = rand() % 10;
int j = 0, ind = 0;
cnt = 0;
for(i = 0; i < 100; ++ i)
{
for(j = 0; j <= arr2[i]; ++ j)
{
ind = arr1[cnt ++];
fprintf(fp_out, "%s", numDic[ind]);
}
fprintf(fp_out, "\n");
}
fclose(fp_in);
fclose(fp_out);
return 0;
}
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