您的位置:首页 > 编程语言 > Java开发

java 生成json与解析

2015-12-21 10:59 519 查看
在JAVA中构造和解析JSON我用的是org.json,附件为相应的org.json.jar.

下面是两个函数,一个是创建JSON,一个是从文本构造JSON并解析之。

创建json

//construct json and output it

public String jsonTest() throws JSONException{

JSONObject json=new JSONObject();

JSONArray jsonMembers = new JSONArray();

JSONObject member1 = new JSONObject();

member1.put("loginname", "zhangfan");

member1.put("password", "userpass");

member1.put("email","10371443@qq.com");

member1.put("sign_date", "2007-06-12");

jsonMembers.put(member1);

JSONObject member2 = new JSONObject();

member2.put("loginname", "zf");

member2.put("password", "userpass");

member2.put("email","8223939@qq.com");

member2.put("sign_date", "2008-07-16");

jsonMembers.put(member2);

json.put("users", jsonMembers);

return json.toString();

}

解析json

Java代码


//construct json from String and resolve it.

public String jsonTest2() throws JSONException{

String jsonString="{\"users\":[{\"loginname\":\"zhangfan\",\"password\":\"userpass\",\"email\":\"10371443@qq.com\"},{\"loginname\":\"zf\",\"password\":\"userpass\",\"email\":\"822393@qq.com\"}]}";

JSONObject json= new JSONObject(jsonString);

JSONArray jsonArray=json.getJSONArray("users");

String loginNames="loginname list:";

for(int i=0;i<jsonArray.length();i++){

JSONObject user=(JSONObject) jsonArray.get(i);

String userName=(String) user.get("loginname");

if(i==jsonArray.length()-1){

loginNames+=userName;

}else{

loginNames+=userName+",";

}

}

return loginNames;

}

转载:http://zhangfan822.iteye.com/blog/1880830
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: