Scala之Set、Map、TreeSet及TreeMap实例
2015-12-20 17:01
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1、代码
package com.yy.base
import scala.collection.mutable
import scala.collection.mutable.TreeSet
import scala.collection.immutable.TreeMap
/**
* Set、Map、TreeSet、TreeMap实例
*/
object SetMapOps extends App {
println("Set Test:")
val data = mutable.Set.empty[Int]
data ++= List(1,2,3,4)
println(data)
data += 5
println(data)
data --= List(1,2)
println(data)
data += 3
println(data)
data.clear()
println(data)
println("Map Test:")
val map = mutable.Map.empty[String,String]
map("name") = "yy"
map("address") = "bj"
println(map)
println("name:"+map.get("name"))
println("address:" + map("address"))
println("TreeSet Test:")
val treeSet = TreeSet(3,2,1,5,7,6,4)
println(treeSet) //排序后
println("TreeMap Test:")
val treeMap = TreeMap("name"->"yy","address"->"bj")
println(treeMap) //排序后
}
2、结果
Set Test:
Set(1, 2, 3, 4)
Set(1, 5, 2, 3, 4)
Set(5, 3, 4)
Set(5, 3, 4)
Set()
Map Test:
Map(address -> bj, name -> yy)
name:Some(yy)
address:bj
TreeSet Test:
TreeSet(1, 2, 3, 4, 5, 6, 7)
TreeMap Test:
Map(address -> bj, name -> yy)
package com.yy.base
import scala.collection.mutable
import scala.collection.mutable.TreeSet
import scala.collection.immutable.TreeMap
/**
* Set、Map、TreeSet、TreeMap实例
*/
object SetMapOps extends App {
println("Set Test:")
val data = mutable.Set.empty[Int]
data ++= List(1,2,3,4)
println(data)
data += 5
println(data)
data --= List(1,2)
println(data)
data += 3
println(data)
data.clear()
println(data)
println("Map Test:")
val map = mutable.Map.empty[String,String]
map("name") = "yy"
map("address") = "bj"
println(map)
println("name:"+map.get("name"))
println("address:" + map("address"))
println("TreeSet Test:")
val treeSet = TreeSet(3,2,1,5,7,6,4)
println(treeSet) //排序后
println("TreeMap Test:")
val treeMap = TreeMap("name"->"yy","address"->"bj")
println(treeMap) //排序后
}
2、结果
Set Test:
Set(1, 2, 3, 4)
Set(1, 5, 2, 3, 4)
Set(5, 3, 4)
Set(5, 3, 4)
Set()
Map Test:
Map(address -> bj, name -> yy)
name:Some(yy)
address:bj
TreeSet Test:
TreeSet(1, 2, 3, 4, 5, 6, 7)
TreeMap Test:
Map(address -> bj, name -> yy)
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