Range Sum Query - Immutable

Given an integer array nums, find the sum of the elements between indices
i and j (i ≤ j), inclusive.

Example:

Given nums = [-2, 0, 3, -5, 2, -1]

sumRange(0, 2) -> 1
sumRange(2, 5) -> -1
sumRange(0, 5) -> -3

Note:

You may assume that the array does not change.
There are many calls to sumRange function.

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class NumArray {
private:
vector<int> sumUntilNow;
int curSum;
public:
NumArray(vector<int> &nums) {
curSum = 0;

for (int i=0; i<nums.size(); i++)
{
curSum += nums[i];
sumUntilNow.push_back(curSum);
}
}

int sumRange(int i, int j) {

if (i == 0)
return sumUntilNow[j];

return sumUntilNow[j]-sumUntilNow[i-1];
}
};

// Your NumArray object will be instantiated and called as such:
// NumArray numArray(nums);
// numArray.sumRange(0, 1);
// numArray.sumRange(1, 2);