您的位置:首页 > 编程语言 > Java开发

springMVC 接收表单参数的五种方法

2015-12-17 18:50 513 查看
转:/article/4897547.html

一个普通的表单。



  表单的代码如下:

[java] view
plaincopy

<%@ page language="java" contentType="text/html; charset=UTF-8"

pageEncoding="UTF-8"%>

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">

<html>

<head>

<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">

<title>Add User</title>

<script type="text/javascript">

//添加用户

function addUser() {

var form = document.forms[0];

form.action = "${pageContext.request.contextPath}/user/addUser1";

//form.action = "${pageContext.request.contextPath}/user/addUser2";

//form.action = "${pageContext.request.contextPath}/user/addUser3";

form.method = "post";

form.submit();

}

</script>

</head>

<body>

<form>

<table>

<tr>

<td>账号</td>

<td>

<input type="text" name="userName">

</td>

</tr>

<tr>

<td>密码</td>

<td>

<input type="password" name="password">

</td>

</tr>

<tr>

<td> </td>

<td>

<input type="button" value="提交" onclick="addUser()">

</td>

</tr>

</table>

</form>

</body>

</html>

1、直接把表单的参数写在Controller相应的方法的形参中

[java] view
plaincopy

@RequestMapping("/addUser1")

public String addUser1(String userName,String password) {

System.out.println("userName is:"+userName);

System.out.println("password is:"+password);

return "/user/success";

}

2、通过HttpServletRequest接收

[java] view
plaincopy

@RequestMapping("/addUser2")

public String addUser2(HttpServletRequest request) {

String userName = request.getParameter("userName");

String password = request.getParameter("password");

System.out.println("userName is:"+userName);

System.out.println("password is:"+password);

return "/user/success";

}

 3、通过一个bean来接收

    1)建立一个和表单中参数对应的bean

[java] view
plaincopy

public class User {

private String userName;

private String password;

public String getUserName() {

return userName;

}

public void setUserName(String userName) {

this.userName = userName;

}

public String getPassword() {

return password;

}

public void setPassword(String password) {

this.password = password;

}

}

2)用这个bean来封装接收的参数

[java] view
plaincopy

@RequestMapping("/addUser3")

public String addUser3(User user) {

System.out.println("userName is:"+user.getUserName());

System.out.println("password is:"+user.getPassword());

return "/user/success";

}

 4、通过json数据接收

[java] view
plaincopy

<%@ page language="java" contentType="text/html; charset=UTF-8"

pageEncoding="UTF-8"%>

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">

<html>

<head>

<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">

<title>Add User</title>

<script type="text/javascript" src="${pageContext.request.contextPath}/resource/script/jquery-1.9.1.min.js"></script>

<script type="text/javascript">

$(document).ready(function(){

$("#button_submit").click(function(){

var name = $("#userName").val();

var pass = $("#password").val();

var user = {userName:name,password:pass};//拼装成json格式

$.ajax({

type:"POST",

url:"${pageContext.request.contextPath}/user/addUser4",

data:user,

success:function(data){

alert("成功");

},

error:function(e) {

alert("出错:"+e);

}

});

});

});

</script>

</head>

<body>

<form>

<table>

<tr>

<td>账号</td>

<td>

<input type="text" id="userName" name="userName">

</td>

</tr>

<tr>

<td>密码</td>

<td>

<input type="password" id="password" name="password">

</td>

</tr>

<tr>

<td> </td>

<td>

<input type="button" id="button_submit" value="提交">

</td>

</tr>

</table>

</form>

</body>

</html>

依然可以使用bean来接收json数据

[java] view
plaincopy

@RequestMapping("/addUser4")

public String addUser4(User user) {

System.out.println("userName is:"+user.getUserName());

System.out.println("password is:"+user.getPassword());

return "/user/success";

}

5、使用jQuery的serializeArray() 方法序列化表单元素 或serialize()

    如果表单元素很多,手工拼装成json数据非常麻烦,可以使用jQuery提供的serializeArray()方法序列化表单元素,返回json数据结构数据。

[java] view
plaincopy

<%@ page language="java" contentType="text/html; charset=UTF-8"

pageEncoding="UTF-8"%>

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">

<html>

<head>

<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">

<title>Add User</title>

<script type="text/javascript" src="${pageContext.request.contextPath}/resource/script/jquery-1.9.1.min.js"></script>

<script type="text/javascript">

$(document).ready(function(){

$("#button_submit").click(function(){

//序列化表单元素,返回json数据

var params = $("#userForm").serializeArray();

//也可以把表单之外的元素按照name value的格式存进来

//params.push({name:"hello",value:"man"});

$.ajax({

type:"POST",

url:"${pageContext.request.contextPath}/user/addUser5",

data:params,

success:function(data){

alert("成功");

},

error:function(e) {

alert("出错:"+e);

}

});

});

});

</script>

</head>

<body>

<form id="userForm">

<table>

<tr>

<td>账号</td>

<td>

<input type="text" id="userName" name="userName">

</td>

</tr>

<tr>

<td>密码</td>

<td>

<input type="password" id="password" name="password">

</td>

</tr>

<tr>

<td> </td>

<td>

<input type="button" id="button_submit" value="提交">

</td>

</tr>

</table>

</form>

</body>

</html>

依然可以使用bean来接收json数据:

[java] view
plaincopy

@RequestMapping("/addUser5")

public String addUser5(User user) {

System.out.println("userName is:"+user.getUserName());

System.out.println("password is:"+user.getPassword());

return "/user/success";
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: