hdu 1012 u Calculate e【数学水题】

u Calculate e

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 38462 Accepted Submission(s): 17414

[align=left]Problem Description[/align]
A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

[align=left]Output[/align]
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

[align=left]Sample Output[/align]

n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333

一道水题，循环就可以了，只是没注意，wa 了一次...

#include<stdio.h>
int main()
{
printf("n e\n");
printf("- -----------\n");
printf("0 1\n");
double e=1,tp=1;
for(int i=1;i<=9;++i)
{
tp*=i;
e+=1.0/tp;
if(i<=1)
{
printf("%d %.f\n",i,e);
}
else if(i<3)
{
printf("%d %.1f\n",i,e);
}
else
{
printf("%d %.9f\n",i,e);
}
}
return 0;
}