1041 Be Unique
2015-12-15 21:38
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Being unique is so important to people on Mars that even their lottery is designed in a unique way. The rule of winning is simple: one bets on a number chosen from [1, 104]. The first one who bets on a unique number wins. For
example, if there are 7 people betting on 5 31 5 88 67 88 17, then the second one who bets on 31 wins.
Input Specification:
Each input file contains one test case. Each case contains a line which begins with a positive integer N (<=105) and then followed by N bets. The numbers are separated by a space.
Output Specification:
For each test case, print the winning number in a line. If there is no winner, print "None" instead.
Sample Input 1:
Sample Output 1:
Sample Input 2:
Sample Output 2:
None
example, if there are 7 people betting on 5 31 5 88 67 88 17, then the second one who bets on 31 wins.
Input Specification:
Each input file contains one test case. Each case contains a line which begins with a positive integer N (<=105) and then followed by N bets. The numbers are separated by a space.
Output Specification:
For each test case, print the winning number in a line. If there is no winner, print "None" instead.
Sample Input 1:
7 5 31 5 88 67 88 17
Sample Output 1:
31
Sample Input 2:
5 888 666 666 888 888
Sample Output 2:
None
#include<iostream> #include<stdio.h> #include<vector> #include<string.h> using namespace std; int main(){ int count[10005]; int n = 0; for (; scanf("%d", &n) != EOF;){ memset(count, 0, sizeof(int)* 10005); vector<int>numbers; for (int i = 0; i < n; i++){ int in; scanf("%d", &in); numbers.push_back(in); count[in]++; } bool flag = 0; int index = 0; for (index = 0; index < numbers.size(); index++){ if (count[numbers[index]] == 1){ flag = 1; break; } } if (flag){ cout << numbers[index] << endl; } else{ cout << "None" << endl; } } return 0; }
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