您的位置:首页 > 其它

leetcode Search a 2D Matrix

2015-12-09 20:40 295 查看
原题链接:https://leetcode.com/problems/search-a-2d-matrix/

Description

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

Integers in each row are sorted from left to right.

The first integer of each row is greater than the last integer of the previous row.

For example,

Consider the following matrix:

[

[1, 3, 5, 7],

[10, 11, 16, 20],

[23, 30, 34, 50]

]

Given target = 3, return true.

class Solution {
public:
bool searchMatrix(vector<vector<int>>& matrix, int target) {
if (matrix.empty() || matrix[0].empty()) return false;
n = matrix.size();
for (int i = 0; i < n; i++) {
It p = lower_bound(matrix[i].begin(), matrix[i].end(), target);
if (p != matrix[i].end() && *p == target) return true;
}
return false;
}
private:
int n;
typedef vector<int>::iterator It;
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: