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Defining hashCode() and equals() effectively and correctly

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Java theory and practice: Hashing it out

Defining
hashCode() and equals() effectively and correctly


Every Java object has a
hashCode()
and
an
equals()
method.
Many classes override the default implementations of these methods to provide a higher degree of semantic comparability between object instances. In this installment of Java
theory and practice, Java developer Brian Goetz shows you the rules and guidelines you should follow when creating Java classes in order to define
hashCode()
and
equals()
effectively
and appropriately.

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Brian
Goetz (brian@quiotix.com),
Principal Consultant, Quiotix Corp

27 May 2003

Also available in Russian Japanese



Table
of contents





While the Java language does not provide direct support for associative arrays -- arrays that can take any object as an index -- the presence of the
hashCode()
method
in the root
Object
class
clearly anticipates the ubiquitous use of
HashMap
(and
its predecessor,
Hashtable
).
Under ideal conditions, hash-based containers offer both efficient insertion and efficient retrieval; supporting hashing directly in the object model facilitates the development and use of hash-based containers.


Defining equality

The
Object
class
has two methods for making inferences about an object's identity:
equals()
and
hashCode()
.
In general, if you override one of these methods, you must override both, as there are important relationships between them that must be maintained. In particular, if two objects are equal according to the
equals()
method,
they must have the same
hashCode()
value
(although the reverse is not generally true).

The semantics of
equals()
for
a given class are left to the implementer; defining what
equals()
means
for a given class is part of the design work for that class. The default implementation, provided by
Object
,
is simply reference equality:

public boolean equals(Object obj) {
return (this == obj);
}


Under this default implementation, two references are equal only if they refer to the exact same object. Similarly, the default implementation
of
hashCode()
provided
by
Object
is
derived by mapping the memory address of the object to an integer value. Because on some architectures the address space is larger than the range of values for
int
,
it is possible that two distinct objects could have the same
hashCode()
.
If you override
hashCode()
,
you can still use the
System.identityHashCode()
method
to access this default value.


Overriding equals() -- a simple example

An identity-based implementation for
equals()
and
hashCode()
is
a sensible default, but for some classes, it is desirable to relax the definition of equality somewhat. For example, the
Integer
class
defines
equals()
similarly
to this:

public boolean equals(Object obj) {
return (obj instanceof Integer
&& intValue() == ((Integer) obj).intValue());
}


Under this definition, two
Integer
objects
are equal only if they contain the same integer value. This, along with
Integer
being
immutable, makes it practical to use an
Integer
as
a key in a
HashMap
.
This value-based approach to equality is used by all the primitive wrapper classes in the Java class library, such as
Integer
,
Float
,
Character
,
and
Boolean
,
as well as
String
(two
String
objects
are equal if they contain the same sequence of characters). Because these classes are immutable and implement
hashCode()
and
equals()
sensibly,
they all make good hash keys.


Why override equals() and hashCode()?

What would happen if
Integer
did
not override
equals()
and
hashCode()
?
Nothing, if we never used an
Integer
as
a key in a
HashMap
or
other hash-based collection. However, if we were to use such an
Integer
object
for a key in a
HashMap
,
we would not be able to reliably retrieve the associated value, unless we used the exact same
Integer
instance
in the
get()
call
as we did in the
put()
call.
This would require ensuring that we only use a single instance of the
Integer
object
corresponding to a particular integer value throughout our program. Needless to say, this approach would be inconvenient and error prone.

The interface contract for
Object
requires
that if two objects are equal according to
equals()
,
then they must have the same
hashCode()
value.
Why does our root object class need
hashCode()
,
when its discriminating ability is entirely subsumed by that of
equals()
?
The
hashCode()
method
exists purely for efficiency. The Java platform architects anticipated the importance of hash-based collection classes -- such as
Hashtable
,
HashMap
,
and
HashSet
--
in typical Java applications, and comparing against many objects with
equals()
can
be computationally expensive. Having every Java object support
hashCode()
allows
for efficient storage and retrieval using hash-based collections.

Back
to top


Requirements for implementing equals() and hashCode()

There are some restrictions placed on the behavior of
equals()
and
hashCode()
,
which are enumerated in the documentation for
Object
.
In particular, the
equals()
method
must exhibit the following properties:

Symmetry: For two references,
a
and
b
,
a.equals(b)
if
and only if
b.equals(a)


Reflexivity: For all non-null references,
a.equals(a)


Transitivity: If
a.equals(b)
and
b.equals(c)
,
then
a.equals(c)


Consistency with
hashCode()
:
Two equal objects must have the same
hashCode()
value

The specification for
Object
offers
a vague guideline that
equals()
and
hashCode()
be consistent --
that their results will be the same for subsequent invocations, provided that "no information used in equals comparison on the object is modified." This sounds sort of like "the result of the calculation shouldn't change, unless it does." This vague statement
is generally interpreted to mean that equality and hash value calculations should be a deterministic function of an object's state and nothing else.

Back
to top


What should equality mean?

The requirements for
equals()
and
hashCode()
imposed
by the Object class specification are fairly simple to follow. Deciding whether, and how, to override
equals()
requires
a little more judgment. In the case of simple immutable value classes, such as
Integer
(and
in fact for nearly all immutable classes), the choice is fairly obvious -- equality should be based on the equality of the underlying object state. In the case of
Integer
,
the object's only state is the underlying integer value.

For mutable objects, the answer is not always so clear. Should
equals()
and
hashCode()
be
based on the object's identity (like the default implementation) or the object's state (like Integer and String)? There's no easy answer -- it depends on the intended use of the class. For containers like
List
and
Map
,
one could have made a reasonable argument either way. Most classes in the Java class library, including container classes, err on the side of providing an
equals()
and
hashCode()
implementation
based on the object state.

If an object's
hashCode()
value
can change based on its state, then we must be careful when using such objects as keys in hash-based collections to ensure that we don't allow their state to change when they are being used as hash keys. All hash-based collections assume that an object's hash
value does not change while it is in use as a key in the collection. If a key's hash code were to change while it was in a collection, some unpredictable and confusing consequences could follow. This is usually not a problem in practice -- it is not common
practice to use a mutable object like a
List
as
a key in a
HashMap
.

An example of a simple mutable class that defines
equals()
and
hashCode()
based
on its state is
Point
.
Two
Point
objects
are equal if they refer to the same
(x,
y)
coordinates, and the hash value of a
Point
is
derived from the IEEE 754-bit representation of the
x
and
y
coordinate
values.

For more complex classes, the behavior of
equals()
and
hashCode()
may
even be imposed by the specification of a superclass or interface. For example, the
List
interface
requires that a
List
object
is equal to another object if and only if the other object is also a
List
and
they contain the same elements (defined by
Object.equals()
on
the elements) in the same order. The requirements for
hashCode()
are
defined with even more specificity -- the
hashCode()
value
of a list must conform to the following calculation:

hashCode = 1;
Iterator i = list.iterator();
while (i.hasNext()) {
Object obj = i.next();
hashCode = 31*hashCode + (obj==null ? 0 : obj.hashCode());
}


Not only is the hash value dependent on the contents of the list, but the specific algorithm for combining the hash values of the individual elements is specified as well. (The
String
class
specifies a similar algorithm to be used for computing the hash value of a
String
.)

Back
to top


Writing your own equals() and hashCode() methods

Overriding the default
equals()
method
is fairly easy, but overriding an already overridden
equals()
method
can be extremely tricky to do without violating either the symmetry or transitivity requirement. When overriding
equals()
,
you should always include some Javadoc comments on
equals()
to
help those who might want to extend your class do so correctly.

As a simple example, consider the following class:

class A {
final B someNonNullField;
C someOtherField;
int someNonStateField;
}


How would we write the
equals()
method
for this class? This way is suitable for many situations:

public boolean equals(Object other) {
// Not strictly necessary, but often a good optimization
if (this == other)
return true;
if (!(other instanceof A))
return false;
A otherA = (A) other;
return
(someNonNullField.equals(otherA.someNonNullField))
&& ((someOtherField == null)
? otherA.someOtherField == null
: someOtherField.equals(otherA.someOtherField)));
}


Now that we've defined
equals()
,
we have to define
hashCode()
in
a compatible manner. One compatible, but not all that useful, way to define
hashCode()
is
like this:

public int hashCode() { return 0; }


This approach will yield horrible performance for
HashMap
s
with a large number of entries, but it does conform to the specification. A more sensible implementation of
hashCode()
for
A
would
be like this:

public int hashCode() {
int hash = 1;
hash = hash * 31 + someNonNullField.hashCode();
hash = hash * 31
+ (someOtherField == null ? 0 : someOtherField.hashCode());
return hash;
}


Note that both of these implementations delegate a portion of the computation to the
equals()
or
hashCode()
method
of the state fields of the class. Depending on your class, you may also want to delegate part of the computation to the
equals()
or
hashCode()
function
of the superclass. For primitive fields, there are helper functions in the associated wrapper classes that can help in creating hash values, such as
Float.floatToIntBits
.

Writing an
equals()
method
is not without pitfalls. In general, it is impractical to cleanly override
equals()
when
extending an instantiable class that itself overrides
equals()
,
and writing an
equals()
method
that is intended to be overridden (such as in an abstract class) is done differently than writing an
equals()
method
for a concrete class. See Effective Java Programming Language Guide, Item 7 (in Resources)
for some examples and more details about why this is so.

Back
to top


Room for improvement?

Building hashing into the root object class of the Java class library was a very sensible design compromise -- it makes using hash-based containers so much easier and more efficient. However, several criticisms have been made of the approach to and implementation
of hashing and equality in the Java class library. The hash-based containers in
java.util
are
very convenient and easy to use, but may not be suitable for applications that require very high performance. While most of these will never be changed, it is worthwhile to keep in mind when you're designing applications that rely heavily on the efficiency
of hash-based containers. These criticisms include:

Too small a hash range. Using
int
,
instead of
long
,
for the return type of
hashCode()
increases
the possibility of hash collisions.

Bad distribution of hash values. The hash values for short strings and small integers are themselves small integers, and are close to the hash values of other "nearby" objects. A more well-behaved hash function would distribute the hash values more evenly across
the hash range.

No defined hashing operations. While some classes, such as
String
and
List
,
define a hash algorithm to be used in combining the hash values of its constituent elements into a single hash value, the language specification does not define any approved means of combining the hash values of multiple objects into a new hash value. The
trick used by
List
,
String
,
or the example class
A
discussed
earlier in Writing
your own equals() and hashCode() methods are simple, but far from mathematically ideal. Nor does the class library offer convenience implementations of any hashing algorithm that would simplify the creation of more sophisticated
hashCode()
implementations.

Difficulty writing
equals()
when
extending an instantiable class that already overrides
equals()
.
The "obvious" ways to define
equals()
when
extending an instantiable class that already overrides
equals()
all
fail to meet the symmetry or transitivity requirements of the
equals()
method.
This means that you must understand the structure and implementation details of classes you are extending when overriding
equals()
,
and may even need to expose private fields in the base class as protected to do so, which violates principles of good object-oriented design.

Back
to top


Summary

By defining
equals()
and
hashCode()
consistently,
you can improve the usability of your classes as keys in hash-based collections. There are two approaches to defining equality and hash value: identity-based, which is the default provided by
Object
,
and state-based, which requires overriding both
equals()
and
hashCode()
.
If an object's hash value can change when its state changes, be sure you don't allow its state to change while it is being used as a hash key.
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